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zlopas [31]
3 years ago
13

the length of a playground is 40 yards and the width of the playground is 30 yatds. tanya is going to run around the sides of th

e playground to get to the opposite corner. maria is gping to run across the diagonal of the playground. who will run firther?
Mathematics
1 answer:
Maru [420]3 years ago
3 0

Answer:

Maria (I THINK)

Step-by-step explanation:

Tanya is running 70 yards in all, while maria would be running more based on the pythagorean theorem

The pythagorean theorem is that on a right triangle, the square root of the two legs equal the hypotenuse

40^2+ 70^2 =c^2

6500=c^2

square root both sides

and roughly c= 80.6 yards so maria runs more

(Im not sure it is a right angle though?)

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Find the surface area of a cylinder with a height of 7 m and a base radius of 5 m.
nekit [7.7K]

Answer: 376.8m

Step-by-step explanation:

Total surface area of a cylinder is calculated by 2πrh+2πr2, where π is a constant, given as 3.14, h is the height= 7m and r is radius= 5m

rh = 5m x 7m = 35m while

r^2 = 5m x 5m = 25m

Slot the values into the formula:

V = 2 x 3.14 ( 35) + 2 x 3.14 (25)

V= (6.28 x 35) + (6.28 x 25)

= 219.8 + 157

V= 376.8m

I hope this helps.

5 0
4 years ago
Read 2 more answers
1. Algebra Find the values for x and y in ABCD.
Marta_Voda [28]

ANSWER

x=12, y=10

EXPLANATION

The diagonals of a parallelogram bisect each other.

This implies that;

AE=EC

4x = 5y - 2

4x - 5y =  - 2...(1)

Also, DE=EB;

2x = y + 14

y =2x - 14...(2)

Put equation (2) in (1).

4x - 5(2x - 14) =  - 2

Expand;

4x - 10x + 70 =  - 2

- 6x =  - 72

x = 12

Put x=2, into equation (2).

y = 2(12) - 14

y = 10

3 0
3 years ago
This is hard broooooooooo
timofeeve [1]

Thes answer would be 51 or -51

6 0
3 years ago
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Find the area of the shaded region.
Lyrx [107]
1)
Area of bigger rectangle
A = (x+1)(x+1) = x^2 + 2x + 1

2)
Area of smaller rectangle
A = 5(x - 7) = 5x - 35

3)
The difference:
(x^2 + 2x + 1) - (5x - 35)
= x^2 + 2x + 1 - 5x +35
= x^2 - 3x + 36

area of the shaded region = x^2 - 3x + 36
6 0
4 years ago
Read 2 more answers
The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\
x>1 \ \land \ x \not= 2 \\
x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\
(x-1)^2=9 \\
\sqrt{(x-1)^2}=\sqrt{9} \\
|x-1|=3 \\
x-1=3 \ \lor \ x-1=-3 \\
x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\
-3=\sqrt{5 \times (-3)+24} \\
-3=\sqrt{-15+24} \\
-3=\sqrt{9} \\
-3=3
It's not true so -3 isn't a solution to this equation.
4 0
3 years ago
Read 2 more answers
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