Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
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Answer:
b=2.5
p=6
Step-by-step explanation:
Take the fraction and simplify it. So 10/8 would be 5/4
You multiply the 2 by 2, giving you h/4
So now you have 5/4=h/4
h=5 but now you have to divide both by 2 again so it can go back to the original fraction.
5÷2=2.5 and 4÷2=2
Second Problem! 4/2 is equal to 2/1
You can also multiply 4 by 3 to get the numerator as 12. Multiply the 4 by 3 and the 2 by 3
Now you have 12/6= 12/p
So p is 6
The first step in solving this problem is to compute the amount
of markup. You can do this by deducting the original price to the marked up
price.
$70.00 - $35.50 = $34.50
To get the percent of markup, you have to divide the amount
of markup to the original price.
$34.50 / $35.50 = 97.2%
