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3 years ago

Find the quotient. Simplify your answer. 7y/6 divides by z/-2

Mathematics

1 answer:

HACTEHA [7]3 years ago

7 0

Answer:

-7y/3z

Step-by-step explanation:

When dividing fractions, we flip the second one so that we can multiply the 2 fractions. When we do this, we get 7y/6 * -2/z. When we multiply the numerators and denominators, we get -14y/6z. Simplifying (dividing the numerator and denominator by 2), we get -7y/3z.

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A company interested in lumbering rights for a certain tract of slash pine trees is told that the mean diameter of these trees i

brilliants [131]

Answer:

97.6% of the trees will have diameters between 7.6 and 18.6 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 12 inches

Standard Deviation, σ = 2.2 inches

We are given that the distribution of diameter of tree is a mound shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(diameters between 7.6 and 18.6 inches)

$P(7.6 \leq x \leq 18.6) = P(\displaystyle\frac{7.6 - 12}{2.2} \leq z \leq \displaystyle\frac{18.6-12}{2.2}) = P(-2 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -2)\\= 0.999 - 0.023 = 0.976= 97.6\%$

$P(7.6 \leq x \leq 18.6) = 97.6\%$

97.6% of the trees will have diameters between 7.6 and 18.6 inches.

8 0

3 years ago

Find P(6) when p = 0.45

Finger [1]

Answer:

2.7

Step-by-step explanation:

6 0

3 years ago

What is the volume of the prism?

jolli1 [7]

V=a*b*c, a=(2+1/2), b=(2+1/2), c=(6+1/2)
V=(2+1/2)*(2+1/2)*(6+1/2) = 15/2 = 7+1/2
(seven whole and one second)

7 0

1 year ago

Read 2 more answers

Which is the decimal equivalent of 2/3 A. 0.23 OB. 0.32 O c. 0.3 O D. 0.6

creativ13 [48]

The answer is d 0.6.......

7 0

3 years ago

Read 2 more answers

At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye

Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that $\mu = 3125$

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that $n = 9, X = 2915, s = 585$

What is the test statistic needed to evaluate the claim?

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}$

$t = -1.08$

The test statistic needed to evaluate the claim is t = -1.08.

6 0

2 years ago