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Answer:
Head bands: 18.58 inches of fabric
Wrist bands : 8.51 inches of fabric
Step-by-step explanation:
Jillian is making accessories for the soccer team.
For head bands
She uses 761.78 inches of fabric on headbands for 39 players and 2 coaches.
The total number of people = 39 player + 2 coaches = 41 people
Hence:
41 persons = 761.78 inches of fabric
1 person = x
Cross Multiply
41 × x = 761.78 × 1
x = 761.78/48
x = 18.58 inches
For wristbands
She also uses 331.89 inches of fabric on wristbands for just the players.
Number of players = 39 players
Hence:
39 players = 331.89 inches
1 players = x inches
Cross Multiply
39 × x = 1 × 331.89 inches
x = 331.89 inches/39
x = 8.51 inches
Therefore:
18.58 inches of fabric was used for head bands and 8.51 inches of fabrics was used for wristbands.
Formula for Perimeter of Rectangle:
P = 2(L + W)
Plug in 160:
160 = 2(L + W)
L = 4W
So we can plug in '4W' for 'L' in the first equation.
<span>160 = 2(L + W)
160 = 2(4W + W)
Combine like terms:
160 = 2(5W)
160 = 10W
Divide 10 to both sides:
W = 16
Now we can plug this back into any of the two equations to find the length.
L = 4W
L = 4(16)
L = 64
So the width is 16, and the length is 64.</span>
The linear equation representing the above said pair of points is "y=12x+9"
Step-by-step explanation:
The given set of points are
x Y
1 21
2 33
3 45
4 57
For finding the linear equation for the given sets of value
We must know the generic form of a linear equation is y=m*x + c
m= slope of the line where y= Δy/Δx
Δy= change in y value
Δx= change in x value
Thus slope ”m” = 33-21/2-1 = 12
we put slope “m” in the equation which becomes y=12x+c
Now we put any of the set value in the equation
33= 12*2+c ∴ c=9
Hence required linear equation is y=12x+9
Find the mean of the first four test scores first.
(Add all numbers in set and divide by how many numbers there are)
81 + 87 + 71 + 89 = 328 / 4 = 82
Then, find the mean with the 85 added as the fifth term.
81 + 87 + 71 + 89 + 85 = 413 / 5 = 82.6
The impact that the 85 had on the mean test score was that the mean/average increased by 0.6.