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kykrilka [37]
4 years ago
15

Solve for x: 1 1/5x−2 1/3<1/7x+1 1/2

Mathematics
1 answer:
Mashcka [7]4 years ago
5 0

Answer: x

Step-by-step explanation:

1\frac{1}{5}x-2\frac{1}{3}

Add 2\frac{1}{3} on both sides and subtract \frac{1}{7}x on both sides to leave x's on the left side and independent values on the right.

(2\frac{1}{3}-\frac{1}{7}x) +1\frac{1}{5}x-2\frac{1}{3}

1\frac{1}{5}x-\frac{1}{7}x

Solve the fractions.

1(\frac{1}{5}-\frac{1}{7})x

1(\frac{(1)(7)-(5)(1)}{(5)(7)} )x

1(\frac{7-5}{35} )x

1(\frac{2}{35} )x

1\frac{2}{35}x

Convert the mixed fraction 1\frac{2}{35} to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

\frac{37}{35}x

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.

(\frac{35}{37}) (\frac{37}{35})x

x

x

x

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Answer:

2

Step-by-step explanation:

7x + 3 = 8x + 1

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these are geometry problems.

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3 years ago
Can someone help me solve this problems
Anvisha [2.4K]

x = 4 and x = - 9

In both cases the angles inside the parallel lines are same sided interior angles

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Similarly

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7 0
4 years ago
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Vera_Pavlovna [14]

Answer:

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Hope this helps!!

7 0
3 years ago
Read 2 more answers
Let f(x) = x^2 + 6x.
rusak2 [61]

Answer:

(A) The slope of secant line is 18.

(B) The slope of secant line is h+16.

Step-by-step explanation:

(A)

The given function is

f(x)=x^2+6x

At x=3,

f(3)=(3)^2+6(3)=27

At x=9,

f(9)=(9)^2+6(9)=135

The secant line joining (3,27) and (9,135). So, the slope of secant line is

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{135-27}{9-3}=18

The slope of secant line is 18.

(B)

The given function is

f(x)=x^2+6x

At x=5,

f(5)=(5)^2+6(5)=55

At x=5+h,

f(5+h)=(5+h)^2+6(5+h)=h^2 + 16 h + 55

The secant line joining (5,55) and (5+h,h^2 + 16 h + 55). So, the slope of secant line is

m=\dfrac{h^2 + 16 h + 55-55}{5+h-5}

m=\dfrac{h^2 + 16 h }{h}

m=h+16

The slope of secant line is h+16.

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4 years ago
Equations of Exponential Functions
puteri [66]

Answer:

D. 46.5%

Step-by-step explanation:

I calculated it logically

6 0
3 years ago
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