Problem 3
Circumference = pi*diameter
C = pi*d
C = 3.14*7.6
C = 23.864
C = 23.9
<h3>Answer: 23.9 cm</h3>
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Problem 4
A = area of square
A = side*side
A = 8*8
A = 64 square cm
B = area of circle
B = pi*r^2
B = 3.14*(5.5)^2 .... radius = 5.5 is half of diameter = 11
B = 94.985
C = area of shaded region
C = B - A
C = 94.985 - 64
C = 30.985
<h3>Answer: 30.985 square cm</h3>
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Problem 5
diameter = 6
radius = 3
area = pi*radius^2
A = pi*r^2
A = pi*3^2
A = 9*pi
A = 9*3.14
A = 28.26
<h3>Answer: 28.26 square millimeters</h3>
<span>$60.00 - $42.00 = </span><span>$18
</span><span>$18 / $60 = 0.30 = 30%
Answer
Decrease 30%</span>
Answer:
perpendicular lines
Step-by-step explanation:
Answer:
9pi approximately 28
Step-by-step explanation:
we have the formula - pi r^2
which we know the diameter is 6 m and the surface is a semi circle
the radius is 3 so then we have pi 3^2
which becomes 9pi which is about 28.2
rounding to 28
hope this helps!!
Answer:
2
Step-by-step explanation:
2/3 times 4 sets is 8/3, which simplifies to 2 1/3. but you cant have 1/3 of a package so you round to 2
