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KengaRu [80]
3 years ago
13

What is the probability that the product of two dice is greater than 15 on two separate rolls?

Mathematics
1 answer:
ratelena [41]3 years ago
4 0

Answer:

25/324

Step-by-step explanation:

Make a table of possible products:

\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&1&2&3&4&5&6\\2&2&4&6&8&10&12\\3&3&6&9&12&15&18\\4&4&8&12&16&20&24\\5&5&10&15&20&25&30\\6&6&12&18&24&30&36\end{array}\right]

Of the 36 results, 10 are greater than 15.

The probability the product is greater than 15 on a single roll is 10/36 = 5/18.

The probability the product is greater than 15 on two rolls is (5/18)² = 25/324.

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maria purchased a new jacket for 78.12. the orginal price of the jacket was discounted 20% and Maria had to pay 5% sales tax. wh
prohojiy [21]
20 percent of the discount minus 5 percent sales tax equals to 15 percent.
know calculate the 15 percentage out of 78,12 so x on 78,12 equals to 20 on 100 so 78,12 equals to 100 percent and x equals to 15 percent so 78,12 times 15 divided by 100 is 15 percent or the number you found discount and and sales tax combined know you substact 15 percent out of your original price.


7 0
3 years ago
The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of
romanna [79]

Answer: a) \dfrac{3}{874}

b) \dfrac{30}{3059}

c) \dfrac{3575}{12236}

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : 11+13=24

Total number of ways to structure a jury of six people from a group of 24 people :-

^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596

a) Number of ways of selecting a jury of all​ students :-

^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{462}{134596}=\dfrac{3}{874}

b) Number of ways of selecting a jury of all​ faculty :-

^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{1716}{134596}=\dfrac{30}{3059}

c) Number of ways of selecting a jury of two students and four ​faculty :-

^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325

Then , the probability of selecting a jury of all​ students :-

\dfrac{39325}{134596}=\dfrac{3575}{12236}

3 0
3 years ago
HELP When does expanding and simplifying a(b + c) result in a positive value for ac?
Reil [10]

Answer:

When c and a are positive or both are negative

Step-by-step explanation:

negative times negative equals positive so if a was negative and c was negative -a*-c= ac

Of course positive times positive equals negative so if a and c were positive we could do

a*c= ac

Hope I could help !

7 0
3 years ago
Brainlyyyyyyyyyyyyyy :)
Rashid [163]
Wow, that IS really BRAINLY! I’m so jealous
6 0
3 years ago
Y = |x-4|+6 The axis of symmetry is x=
Troyanec [42]

Answer:

Y = |x-4|+6 The axis of symmetry is x=xxx se_x.com

Step-by-step explanation:

8 0
3 years ago
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