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Fofino [41]
3 years ago
15

Write an equation in​ slope-intercept form of the line that passes through the given point and is perpendicular to the graph of

the given equation.
(-5,8); y=1/5x-2

Write an equation for the perpendicular line in​ slope-intercept form.
Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

Answer:

y = -5x - 17

Step-by-step explanation:

Linear equations, or lines, that are perpendicular to each other have opposite reciprocals for the value of slope.  For the given line, y = 1/5x - 2, the slope is 1/5 and the opposite reciprocal is -5.

Given the value of the slope and a given point on the second line, you can solve for 'b':

y = mx + b

8 = (-5)(-5) + b

8 = 25 + b

-17 = b

y = -5x - 17

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