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Zielflug [23.3K]
3 years ago
10

-3x+2-5x-7=4x+2 what is the first step solve this equation?

Mathematics
1 answer:
Triss [41]3 years ago
5 0

Answer: x = -0.58

Step-by-step explanation:

-3x+2-5x-7=4x+2

First step, collect like terms

-3x -5x-4x = 2-2+7

-12x = 7

x = 7/-12

x = -0.58

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Find the derivative
zalisa [80]

First use the chain rule; take y=\dfrac{x+5}{x^2+3}. Then

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{\mathrm df}{\mathrm dy}\cdot\dfrac{\mathrm dy}{\mathrm dx}

By the power rule,

f(x)=y^2\implies\dfrac{\mathrm df}{\mathrm dy}=2y=\dfrac{2(x+5)}{x^2+3}

By the quotient rule,

y=\dfrac{x+5}{x^2+3}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)\frac{\mathrm d(x+5)}{\mathrm dx}-(x+5)\frac{\mathrm d(x^2+3)}{\mathrm dx}}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{(x^2+3)-(x+5)(2x)}{(x^2+3)^2}

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3-10x-x^2}{(x^2+3)^2}

So

\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)}{x^2+3}\cdot\dfrac{3-10x-x^2}{(x^2+3)^2}

\implies\dfrac{\mathrm df}{\mathrm dx}=\dfrac{2(x+5)(3-10x-x^2)}{(x^2+3)^3}

6 0
3 years ago
What is the slope of (-13,8) and (3,12)
love history [14]

Answer:

Slope = 1/4

Step-by-step explanation:

Y2 - Y1 / X2 - X1

8 0
3 years ago
Help lol the question is on the picture please help!
valina [46]

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7 0
3 years ago
Which function describes the arithmetic sequence shown?
Lynna [10]

f(x)= -2x-3

Step-by-step explanation:

Step 1:

Let the sequence given here is -5, -7, -9, -11, -13 ......

Here the first term (a₁) of sequence is -5

And the common difference between the numbers in the sequence is

d= (-7-(-5)) = -7+5 = -2

Let the number of terms be x

Step 2;

To find the sequence function basic arithmetic sequence formula is

aₙ = a₁ + d( x-1)

Applying the values we get

f(X) = -5 + ((-2)(X-1))

on simplification

f(X) = -5 + (-2X+2)

f(X)= -5+2-2X

f(X)= -3-2X

8 0
3 years ago
9.
elixir [45]
The first one. Hope this helps
Be glad to tell me if it’s correct or not
7 0
4 years ago
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