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vlada-n [284]
3 years ago
14

Factor the quadratic. 2x^2+5x-12

Mathematics
1 answer:
Sav [38]3 years ago
8 0
2
2x
​2
​​ +5x−12
1 Split the second term in
2
x
2
+
5
x
−
1
2
2x
​2
​​ +5x−12 into two terms.
2
x
2
+
8
x
−
3
x
−
1
2
2x
​2
​​ +8x−3x−12

2 Factor out common terms in the first two terms, then in the last two terms.
2
x
(
x
+
4
)
−
3
(
x
+
4
)
2x(x+4)−3(x+4)

3 Factor out the common term
x
+
4
x+4.
(
x
+
4
)
(
2
x
−
3
)
(x+4)(2x−3)
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3 0
3 years ago
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Solve (6-5x)/10-(2x+1)/5+x/3=2x/15
Ulleksa [173]
Multiply2 * x/15 to 2x/15

multiply both sides by 30 which is the LCM of 10, 5, 3, and 15

expand it

simplify 18 - 15x - 12x - 6 + 10x to 12 - 17x

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divide both sides by 21

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3 0
3 years ago
F(x) = 1/(5x-6)Find the derivative of this function
siniylev [52]

Given

f(x)=\frac{1}{5x-6}

To find the derivative of the give function,we apply below exponent rule first:

\frac{1}{a}=a^{-1}

So,

Next, we apply the chain rule:

So,

We substitute back u=(5x-6):

Simplify:

Therefore, the answer is:

=-\frac{5}{(5x-6)^2}

5 0
1 year ago
Find an equation of the line that is perpendicular to the graph of 2x+5y=5 and contains the point of intersection of the graphs
gavmur [86]

Answer:

  5(x+1) -2(y-3) = 0

Step-by-step explanation:

For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...

  b(x-h) -a(y-k) = 0

A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...

  5(x+1) -2(y-3) = 0

_____

In the attached graph, the requested line is shown in black.

3 0
4 years ago
3x + 9y = -42 -3x + 2y = -2 The solution to the system is
AlladinOne [14]

x=−2 and y=−4

If you need explanation Just ask!

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4 years ago
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