Answer:
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Explanation:
Hope this helped!
According to half life equation:
T(1/2) = ㏑2 / K1
when the T(1/2) = 4 min * 60 = 240 sec
by substitution:
240 = 0.6931 / K1
K1 = 2.9 x 10^-3
when the second T(1/2) = 20 sec, so to get K2:
T(1/2) = 0.6931 / K2
by substitution:
20 = 0.6931 / K2
∴K2 = 3.4 x 10^-2
so, we can get T2 by using this formula:
㏑ (K2/K1) = Ea/R (1/T1 - 1/T2)
by substitution:
㏑(3.4 x 10^-2)/(2.9 x 10^-3) = (24520 / 8.314) (1/298 - 1/T2)
∴ T2 = 396.7 K
= 396.7 - 273 = 123.7 °C
Both carbon and lead belong to Group IV elements, and thus they have the same number of valence electrons.
<span>In
each of the other options, the two elements belong to different groups,
and thus they do NOT have the same number of valence electrons.
I hope this helped you, please tell me if I am correct or not <3
</span>
The number of mole of NaOH that was used, given that 3.85 mL of 10.0 M NaOH is used in the reaction is 0.0385 mole
<h3>How do I determine the number of mole of NaOH?</h3>
We know that molarity is related to number of mole and volume according to the following formula:
Molarity = number of mole / Volume
With the above formula, we can determine the number of mole of NaOH. Details below
The following data were obtained from the question:
- Volume = 3.85 mL = 3.85 / 1000 = 0.00385 L
- Molarity = 10.0 M
- Number of mole of NaOH =?
Molarity = number of mole / Volume
Cross multiply
Number of mole = molarity × volume
Number of mole of NaOH = 10 × 0.00385
Number of mole of NaOH = 0.0385 mole
Thus, the number of mole of NaOH is 0.0385 mole
Learn more about number of mole:
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