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3 years ago

Which law relates to the ideal gas law?

Chemistry

1 answer:

ella [17]3 years ago

4 0

Answer:

equation (4.16) depends on Boyle's law and Charles' law. The above relates the adjustment in perfect gas volume to the progressions in winning weight and temperature, separately. Moreover, equation (4.16) is alluded to as the condition of state for a perfect gas.

hope it helps:))

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PLEASE HELP QUICK!!! Electromagnetic Spectrum Activity Worksheet

Vlad1618 [11]

Answer:

The electromagnetic spectrum is the range of frequencies (the spectrum) of electromagnetic radiation and their respective wavelengths and photon energies. The electromagnetic spectrum covers electromagnetic waves with frequencies ranging from below one hertz to above 10²⁵ hertz, corresponding to wavelengths from thousands of kilometers down to a fraction of the size of an atomic nucleus. This frequency range is divided into separate bands, and the electromagnetic waves within each frequency band are called by different names; beginning at the low frequency (long wavelength) end of the spectrum these are: radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays at the high-frequency (short wavelength) end. The electromagnetic waves in each of these bands have different characteristics, such as how they are produced, how they interact with matter, and their practical applications. There is no known limit for long wavelengths, while it is thought that the short wavelength limit is in the vicinity of the Planck length. Extreme ultraviolet, soft X-rays, hard X-rays and gamma rays are classified as ionizing radiation as their photons have enough energy to ionize atoms, causing chemical reactions. Exposure to these rays can be a health hazard, causing radiation sickness, DNA damage and cancer. Radiation of visible light wavelengths and lower are called nonionizing radiation as they cannot cause these effects.

Explanation:

6 0

3 years ago

Cryolite (Na3AlF6) is used in the production of aluminum from its ores. It is made by the reaction 6 NaOH 1 Al2O3 1 12 HF 8n 2 N

kap26 [50]

<u>Answer:</u> The mass of cryolite produced in the reaction is 1181.8 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium oxide = 287 g

Molar mass of aluminium oxide = 102 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium oxide}=\frac{287g}{102g/mol}=2.814mol$

The given chemical reaction follows:

$6NaOH+Al_2O_3+12HF\rightarrow 2Na_3AlF_6+9H_2O$

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 2.814 moles of aluminium oxide will produce = $\frac{2}{1}\times 2.814=5.628mol$ of cryolite

Now, calculating the mass of cryolite by using equation 1:

Moles of cryolite = 5.628 moles

Molar mass of cryolite = 210 g/mol

Putting values in equation 1, we get:

$5.628mol=\frac{\text{Mass of cryolite}}{210g/mol}\\\\\text{Mass of cryolite}=(5.628mol\times 210g/mol)=1181.8g$

Hence, the mass of cryolite produced in the reaction is 1181.8 g

5 0

3 years ago

Boxes on trees in swamps give wood ducks a place to build their nests platforms built on top of telephone poles provide a place

Rus_ich [418]

These artificial homes preserve the resources in the animal's environment and increases population size.

<h3>What is Population size?</h3>

This is defined as the number of organisms in a population at a given place and time.

Since the resources used are artificial, they are preserved with an increase in the population due to reproduction.

Read more about Population size here brainly.com/question/1502078

#SPJ1

8 0

2 years ago

Can someone help me with this?

Doss [256]

He was involved in the mapping of venus and mars

5 0

3 years ago

Identify the types of intermolecular forces present in each of the following substances, and select the substance in each pair t

Sergeu [11.5K]

Answer:

a. Van der Waals forces, C8H18 has higher boiling point.

b. Van der Waals forces in both compounds

Dipole -Dipole in CH3OCH3

c. Van der Waals and dipole-dipole in both, higher boiling point for HOOH.

Additionally H bonding in HOOH

d. Van der Waals for both compounds, additionally dipole- dipole and hydrogen bonding for NH2NH2.

Higher boling point NH2NH2

Explanation:

To answer this question we have to know the hybridization of the atoms of interest and/or the presence of resultant dipole moments which make the molecule polar, and the van der Waals interactions. Also we have to look for the presence of hydrogen bonding.

Remember van der Waals forces will be present in all of the molecules since they are of the instantaneous type produced by the momentaneous distortions of the electron clouds.

a. These two compounds are hydrocarbons, the electronegativity difference between carbon and hydrogen is very small, so the only factor we need to consider are the van der Waals interactions.

The van der Waals interactions increase with molecular weight since they are interactions which are momentaneous between the atoms in the molecule, and the heavier the molecule the more these distortions are possible.

Since C8H18 has a higher molecular than C6H14, it follows it has a greater boiling point.

b. CH3OCH3 differs only on the added O atom to C3H8. They have similar molecular weights, 46 vs 44 g/mol, but the presence of the tehedral sp³ hybridized oxygen atom with its high electronegativity produces dipole moments and imparts a polarity to the molecule which make us to predict CH3OCH3 will have a higher boiling point.

c. In HOOH we have dipole-dipole moments since the oxygen atom is sp³ hybridized and the O-O-H is tetrahedral, the molecule is polar. Additionally we have the presence of H bond in this compound which is not possible in HSSH.

While the molecule HSSH is also polar since it has two dipole moments in the sp³ hybridized ( tetrahedral ) S, it is not as big as the dipole moment in O-H.

Therefore Hydrogen peroxide, HOOH, has a higher boiling point than HSSH

d. The N-H bond has a dipole moment, and since the N is tetrahedral there is a resultant dipole moment. As in case d., we have hydrogen bonding between H and N.

NH2NH2 then will have a higher boiling point than CH3CH3 where only van der Waals interactions are possible.

You are welcome.

8 0

4 years ago

Which law relates to the ideal gas law?​

Which law relates to the ideal gas law?