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BigorU [14]
2 years ago
12

A 3000 MWt fast reactor has a 42% efficiency. This reactor operates for 23 months followed by a 1 month down time for refueling

and maintenance. If this reactor operates at an average power of 1200 MWe, what is the capacity factor and availability factor over this 2 year period?
Chemistry
1 answer:
n200080 [17]2 years ago
8 0

Answer:

capacity factor = 0.952

Availability factor = 0.958

Explanation:

1) capacity factor

capacity factor = actual power output /  maximum power output

                        = (actual power output)/(efficiency * rated power output)

                       = \frac{1200}{\frac{42}{100}*3000}

= 0.952

2) Availability factor

Availability factor  = Actual operation time period/ total time period

                            = 23/24 = 0.958

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you have been observing an insect that defends itself from enemies by secreting a caustic liquid. analysis of the liquid shows i
Alexus [3.1K]

pH of the buffer solution is 1.76.

Chemical dissociation of formic acid in the water:

HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq)

The solution of formic acid and formate ions is a buffer.

[HCOO⁻] = 0.015 M; equilibrium concentration of formate ions

[HCOOH] + [HCOO⁻] = 1.45 M; sum of concentration of formic acid and formate

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pH = 3.74 + log (0.015 M/1.435 M)

pH = 3.74 - 1.98

pH = 1.76

More about buffer: brainly.com/question/4177791

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4 0
1 year ago
When a substance changes from gas to liquid at a temperature below its boiling point, ____ has taken place.
puteri [66]
That would be evaporation.
Hope this helped!! xx
5 0
3 years ago
Which of a following elements has the Smallest atomic radius 1. Ge 2. SI 3. Carbon 4. Sn​
Artyom0805 [142]

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