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Gennadij [26K]
3 years ago
15

A piece of PVC plumbing pipe displaces 60 mL when placed into a container of water. If the pipe has a mass of 78g, what is the d

ensity of PVC?
Chemistry
2 answers:
Kryger [21]3 years ago
7 0

Answer : The density of PVC pipe is 1.3 g/mL

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

Density=\frac{Mass}{Volume}

Given :

Mass of PVC pipe = 78 grams

Volume of PVC pipe = 60 mL

Now put all the given values in the above formula, we get the density of PVC pipe.

Density=\frac{78g}{60mL}

Density=1.3g/mL

Therefore, the density of PVC pipe is 1.3 g/mL

babymother [125]3 years ago
3 0
Use the equation d=m/v

your mass or "m" is 78 g

your volume or "v" is 60mL

if you plug those values into the equation it will look like this:

d=78/60
d=1.3g/mL should be what you come up with
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Select all of the statements that are true.
Ahat [919]
1 is true, 
<span>2 is definitely false </span>
<span>3 is also completely false because </span>
<span>4 is true. </span>

<span>So 1&4 </span>
5 0
3 years ago
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Why Basalt and gabbro are denser than granite and<br> obsidian?
Maksim231197 [3]

Answer:

What do you think causes some rock types to have higher densities than others? (Assuming there are no air pockets in the rock, the types of minerals will determine the density. Granite contains lots of quartz and feldspar - both fairly light minerals, whereas basalt and gabbro are made of heavier minerals.)

Explanation:

4 0
3 years ago
Caffeine, a stimulant found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 1.000 mg of caffeine
Yuliya22 [10]

Answer:

  • <u>194 g/mol</u>

Explanation:

<u>1) Content of C:</u>

All the C atoms in the 1.000 mg of caffeine will be found in the 1.813 mg of CO₂.

  • Mass of C in 1.813 mg of CO₂

       Since the atomic mass of C is 12.01 g/mol and the molar of of CO₂ is 44.01, there are 12 mg of C in 44 mg of CO₂ and you can set the proporton:

       12.01 mg C / 44.01 mg CO₂ = x / 1.813 g CO₂

        ⇒ x = 1.813 × 12.01 / 44.01 g of C = 0.49475 mg of C

  • Number of moles of C

      number of moles = mass in g / atomic mass = 0.49475×10⁻³ g / 12.01 g/mol = 4.1195×10⁻⁵ moles = 0.041195 milimol

<u>2) Content of H</u>

All the H atoms in the 1.000 mg of caffeine will be found in the 0.4639 mg of H₂O

  • Mass of H in 0.4639 mg of H₂O

       Since the atomic mass of H is 1.008 g/mol and the molar of of H₂O is 18.015 g/mol, there are 2×1.008 mg of H in 18.015 mg of H₂O and you can set the proporton:

       2×1.008 mg H / 18.015 mg H₂O = x / 0.4639 mg H₂O

        ⇒ x = 0.4639 mg H₂O × 2 × 1.008 mg H / 18.015 mg H₂O = 0.051913 mg H

  • Number of moles of H

      number of moles = mass in g / atomic mass = 0.051913 ×10⁻³ g / 1.008 g/mol = 5.1501× 10⁻⁵ moles = 0.051501 milimol

<u>3) Content of N</u>

All the N atoms in the 1.000 mg of caffeine will be found in the 0.2885 mg of N₂

  • Mass of N in 0.2885 mg of N₂ is 0.2885 mg

  • Number of moles of N

      number of moles = mass in g / atomic mass = 0.2885 ×10⁻³ g / 14.007 g/mol = 2.0597× 10⁻⁵ moles = 0.020597 milimol

<u>4) Content of O</u>

The mass of O is calculated by difference:

  • Mass of O = mass of sample - mass of C - mass of H - mass of N

       Mass of O = 1.000 mg - 0.49475 mg C - 0.051913 mg H - 0.2885 mg N

     Mass of O = 0.1648 mg

  • Moles of O =  0.1648 × 10 ⁻³ g / 15.999 g/mol = 1.0303×10⁻⁵ mol = 0.01030 milimol

<u>5) Ratios</u>

Divide every number of mililmoles by the smallest number of milimoles:

  • C:  0.041195 / 0.01030 = 4
  • H: 0.051501 / 0.01030 = 5
  • N: 0.020597 / 0.01030 = 2
  • O: 0.01030 / 0.01030 = 1

  • C: 4
  • H: 5
  • N: 2
  • O: 1

<u>6) Empirical formula:</u>

  • C₄H₅N₂O₁

<u>7) Calculate the approximate mass of the empirical formula:</u>

  • 4 × 12 + 5 × 1 + 2 × 14 + 1 × 16 =  97 g/mol

So, since that number is not between 150 and 200 g/mol, multiply by 2: 97 × 2 = 194, which is between 150 and 200.

Thus, the estimate is 194 g/mol

7 0
3 years ago
A ball is moving at a speed of 6.70 m/s. If the kinetic energy of the ball is 3.10 J, what is the mass of the ball?​
Anni [7]

Answer:

<h2>0.14 kg</h2>

Explanation:

The mass of the ball can be found by using the formula

m =  \frac{2k}{ {v}^{2} }  \\

v is the velocity

k is the kinetic energy

From the question we have

m =  \frac{2(3.10)}{ {6.70}^{2} }  =  \frac{6.20}{44.89}  \\  = 0.138115...

We have the final answer as

<h3>0.14 kg</h3>

Hope this helps you

7 0
3 years ago
How much grams are in 4.78 cup
Aleksandr [31]

Answer:

1130.89

Explanation:

5 0
3 years ago
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