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AlladinOne [14]
2 years ago
5

A pizza with a diameter of 13 inches is cut into 12 equal slices. Jayden eats 1/3 of the pizza, representing an area of ____ squ

are inches. Carson eats 5 slices of pizza, representing an area of ____ square inches.
Mathematics
1 answer:
Len [333]2 years ago
4 0

Answer:

Jayden 44.2433333 inches squared

Carson 55.3041665 inches squared

Step-by-step explanation:

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ASAP can someone help me solve this problem​
sveta [45]

Answer:

Step-by-step explanation:

x° + y° = 180°

2y° - 0.5x° = 180°

y° = 108°

x° = 72°

3 0
3 years ago
15% of 60 is what percent of 180?
aivan3 [116]
Okay so uh i think it’s this: 15% of 60=0.15* 60=9
9 is what percent of 180 i think..?
9/180=1/20=5/100=5%
7 0
2 years ago
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If each person takes up 2.25 square feet of space, how many people can fit into an area that is 15 feet by 30 feet?
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D is the answer Multiply 15 times 30 and divide by 2.25
7 0
2 years ago
If a semi truck's trailer is 40 feet long, 10 feet wide, and has a height of 8 feet, what is its volume?
Temka [501]

First multiply 40 and 10 to get 400. Then multiply 400 by 8 to get 3,200.

Your answer would be: 3,200

8 0
3 years ago
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
eimsori [14]

Answer:

There are NO real roots for this equation. The only roots have imaginary parts and therefore cannot be represented on the real x-axis.

Step-by-step explanation:

We notice that the expression on the left of the equation is a quadratic with leading term 2x^2, which means that its graph is that of a parabola with branches going up.

Therefore, there can be three different situations:

1) if its vertex is ON the x axis, there would be one unique real solution (root) to the equation.

2) if its vertex is below the x-axis, the parabola's branches are forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will have NO real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently.

We recall that the x-position of the vertex for a quadratic function of the form  f(x)=ax^2+bx+c is given by the expression:

x_v=\frac{-b}{2a}

Since in our case a=2 and b=-3, we get that the x-position of the vertex is:

x_v=\frac{-b}{2a}\\x_v=\frac{-(-3)}{2(2)}\\x_v=\frac{3}{4}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = 3/4:

y_v=f(\frac{3}{4})=2( \frac{3}{4})^2-3(\frac{3}{4})+4\\f(\frac{3}{4})=2( \frac{9}{16})-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{9}{4}+4\\f(\frac{3}{4})=\frac{9}{8}-\frac{18}{8}+\frac{32}{8}\\f(\frac{3}{4})=\frac{23}{8}

This is a positive value for y, therefore we are in the situation where there is NO x-axis crossing of the parabola's graph, and therefore no real roots.

We can though estimate a few more points of the parabola's graph in order to complete the graph as requested in the problem. For such we select a couple of x-values to the right of the vertex, and a couple to the right so we can draw the branches. For example: x = 1, and x = 2 to the right; and x = 0 and x = -1 to the left of the vertex:

f(-1) = 2(-1)^2-3(-1)+4= 2+3+4=9\\f(0)=2(0)^2-3(0)+4=0+0+4=4\\f(1)=2(1)^2-3(-1)+4=2-3+4=3\\f(2)=2(2)^2-3(2)+4=8-6+4=6

See the graph produced in the attached image.

4 0
2 years ago
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