A=P(1/2)^(t/h)
P=initial amount
t=time
h=half life
A=final amount
so
A=0.242188 grams
Answer:
(h o k)(3) = 3
(k o h)(-4b) = -4b
Step-by-step explanation:
If f(x) and g(x) are inverses, then (f o g)(x) = (g o f)(x) = x
(h o k)(3) = 3
(k o h)(-4b) = -4b
Remark
This is quite a nice little problem. It takes a minute or three to figure out the answer, and when you do, you will be certain that you have been tricked. It is a little like the egg of Columbus.
Solution
The Base of Triangle ABN is AB
The Base of Triangle CDM is CD
The height of both given triangles is h. That is the distance between the two parallel lines.
Area ABN = 1/2*AB * h = 23 cm^2
Area CDM = 1/2*CD * h = 18 cm^2
Now the Area of the trapezoid is
Area_Trapezoid = 1/2 * h (AB + CD) Using the distributive property Remove the brackets.
Area_Trapezoid = 1/2*AB*h + 1/2*CD*h Did you notice something? Those terms are just the area of the triangles (written above.)
Area Trapezoid = 23 + 18 = 41 cm^2 <<<< Answer
<span>7.25 = 7 and 25/100 = 7 and 1/4</span>
We can plug those values into the equation, and if the answer is incorrect, we'll know if either one is extraneous.
√11 - 2(-7) = √(-7)^2 + 4(-7) + 4
√25 = √25
5 = 5
The first solution, -7, makes the equation true, and so it is not extraneous.
√11 - 2(1) = √(1)^2 + 4(1) + 4
√9 = √9
3 = 3
The second solution, 1, makes the equation true, and so it is also not extraneous.
<h3>The correct option is D, neither solution is extraneous. </h3>
