Answer:
P(A ∩ B) = 0.
a) NO
b) YES
Step-by-step explanation:
Thinking about this through Venn diagrams we can sort of understand that:
if P(A) = 0.2 and P(B) = 0.2, and P(A∪B) = 0.4.
there's no overlapping between P(A) and P(B).
(If there was overlapping then P(A∪B) < 0.4, since you'd be excluding the overlapped part from getting counted twice.
Think of it in terms of calculating areas circles A and B, if the circles were disjoint, then the sum of the areas A and B would be 0.2+0.2. But if the circles were overlapping then the sum of the areas would be 0.2+0.2-P(A ∩ B), where P(A ∩ B) is the overlapping part)
since there's no overlapping P(A ∩ B) = 0.
a) NO
events A and B are only independent when P(A ∩ B) > 0 (or overlapping)
b) YES
events A and B are mutually exclusive when P(A ∩ B) = 0 (or disjoint)
Answer:
C
Step-by-step explanation:
The answer is C.
9u means you're multiplying 9 into that vector, both components. Same with the 2v. 9*3 = 27 and 9*-1 = -9, so your new vector u is <27, -9>. Now let's do v. 2* -6 (twice) = -12, so your new v vector is <-12, -12>. Add those together now, first components of each and second components of each. 27 + (-12) = 15; -9+(-12)=-21. So the addition of those gives us a final vector with a displacement of <15, -21>
I think it is a direct variation because if you divide 9/3, 27/3, 39/13, and 60/20 it will all give you the same number which is 3.
I hope this helps.
C is the awnser to that question
