Answer:
20
Step-by-step explanation:
Answers:
1) (s o t)(x)=4x^2-x-4
2) (t o s)(x)=4(x-7)^2-(x-7)+3
Solution:
1) (s o t)(x)=s(t(x))=s(4x^2-x+3)=(4x^2-x+3)-7=4x^2-x+3-7
(s o t)(x)=4x^2-x-4
2) (t o s)(x)=t(s(x))=t(x-7)=4(x-7)^2-(x-7)+3
(t o s)(x)=4(x-7)^2-(x-7)+3
ANSWER
EXPLANATION
The prime factorization of the two numbers are
and
To find the least common multiple , we collect the factors with the powers and multiply them out.
The highest power of 2 is
The highest power of 3 is
The highest power of 5 is
and the highest power of 7 is
Therefore
I would use a proportion
45students/60% = Xstudents/100% (cross multiply)
x=75 students