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diamong [38]
3 years ago
9

2. Angelica reflects ABCDE over the yaxis and translates to Does her transformed figure match A'B' C D'Ef not describe honored f

igure compares to A"B" C" D'E Wuitenwein besondebele​
Mathematics
2 answers:
Monica [59]3 years ago
5 0

Answer:

╲┏━┳━━━━━━━━┓╲╲

╲┃◯┃╭┻┻╮╭┻┻╮┃╲╲

╲┃╮┃┃╭╮┃┃╭╮┃┃╲╲

╲┃╯┃┗┻┻┛┗┻┻┻┻╮╲

╲┃◯┃╭╮╰╯┏━━━┳╯╲

╲┃╭┃╰┏┳┳┳┳┓◯┃╲╲

do u like it

Step-by-step explanation:

bekas [8.4K]3 years ago
5 0

Answer:

╲┏━┳━━━━━━━━┓╲╲

╲┃◯┃╭┻┻╮╭┻┻╮┃╲╲

╲┃╮┃┃╭╮┃┃╭╮┃┃╲╲

╲┃╯┃┗┻┻┛┗┻┻┻┻╮╲

╲┃◯┃╭╮╰╯┏━━━┳╯╲

╲┃╭┃╰┏┳┳┳┳┓◯┃╲╲

spogebub

Step-by-step explanation:

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Tyler made a scale drawing of a 24 ft long boat. In his drawing, the boat was 6 inches. The scale that Tyler used for his drawin
defon

Answer:

In Tyler scale, 1 inch equals 4 ft.

Step-by-step explanation:

Giving the following information:

Tyler made a scale drawing of a 24 ft longboat. In his drawing, the boat was 6 inches.

<u>We know that 1 ft is 12 inches. Therefore, 24 ft:</u>

24*12= 288 inches

<u>Now, we have to determine the scale that Tyler used.</u>

<u></u>

1 Tyler inch= 288/6= 48 inches

In ft:

1 Tyler inch= 48/12= 4 ft

In Tyler scale, 1 inch equals 4 ft.

3 0
3 years ago
15x+27 how do you find the GCF
telo118 [61]
The correct answer would be 3 bc it goes into it 3 times!!:-D  hope I helped u
8 0
3 years ago
Read 2 more answers
How do you solve<br> -6n-20=-2n+4 (1-3n)
DedPeter [7]
-6n-20=-2n+4-12n
-6n-20=-14n+4
+6n       +6n
-20=-8n+4
-4          -4
-24=-8n
/8     /8
n=-3
         -
3 0
3 years ago
How many rational numbers are between 1 and 6?
gregori [183]

one ans six are infinite

6 0
3 years ago
Three vertices of the trapezoid are A(4d,4e), B(4f,4e), and C(4g,0). The fourth vertex lies on the origin. Find the midpoint of
satela [25.4K]
We have that

point C and point D have y = 0-----------> (the bottom of the trapezoid).

point A and point B have y = 4e ---------- > (the top of the trapezoid)

the y component of  midpoint would be halfway between these lines
 y = (4e+ 0)/2 = 2e. 

<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.

x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g. 

</span>therefore

the midpoint of the midsegment is (d + f + g, 2e)
8 0
3 years ago
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