Answer:
The required probability is 0.988.
Step-by-step explanation:
Consider the provided information.
Based on a poll, 67% of Internet users are more careful about personal information when using a public Wi-Fi hotspot.
That means the probability of more careful is 0.67
The probability of not careful is: 1-0.67 = 0.33
We have selected four random Internet users. we need to find the probability that at least one is more careful about personal information.
P(At least one careful) = 1 - P(None of them careful)
P(At least one careful) = 1 - (0.33×0.33×0.33×0.33)
P(At least one careful) = 1 - 0.012
P(At least one careful) = 0.988
Hence, the required probability is 0.988.
The result may be higher because of the convenience bias in retrieving the sample. Because the survey subjects volunteered to respond not random.
Can you take a pic of the problem?
Answer:
ft
Step-by-step explanation:
Base=b=8 ft
Hyp=c=?
Perp=a=15 ft
Applying Pythagoras theorem
(x² - 1)^-2/3
∛(x² - 1)-²
∛(1/(x² - 1)(x² - 1))
∛(1/(x^4 - x² - x² + 1))
∛(1/(x^4 - 2x² + 1))
1/x^4/3 - 1.25992105x^2/3 + 1
Derivatives galore. Don't forget you might need to split the function because of the absolute value.
