Answer:
141.78 m
Step-by-step explanation:
Let d = distance of boat from the base of the lighthouse
Tan 10 = 25/d
d tan 10 = 25
d = 25/tan 10
d = 141.78 m
The data set represents the prices, in dollars, of the items students are selling for a fundraiser. 1, 1, 2, 3, 3, 4, 4, 4, 5, 5
lidiya [134]
To produce a box plot, we need the lowest and highest value from the data set. We also need the lower quartile (

), median (

), and upper quartile (

).
All these data and the box plot is shown in the diagram below
Answer:

Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor
so

substitute the given value and solve for JK



Answer:
B.
Step-by-step explanation:
In mathematics, a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a symbol, called the imaginary unit, that satisfies the equation i² = −1. Because no real number satisfies this equation, i was called an imaginary number by René Descartes.
Answer:
313 shapes
Step-by-step explanation:
The nth term is 3n+1
so 3x104=312+1= 313 shapes