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2 years ago

Please help with this question

Mathematics

1 answer:

larisa [96]2 years ago

4 0

Answer:

$c=17$ ft

Step-by-step explanation:

Base=b=8 ft

Hyp=c=?

Perp=a=15 ft

Applying Pythagoras theorem

$c=\sqrt{a^{2} + b^{2} }$

$c=\sqrt{15^{2} + 8^{2} }$

$c=\sqrt{289 }\\c=17$

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What value of x is in the solution set of 4x - 12 s 16 + 8x? 6 Of -10 -7

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Answer:

Your answer is (D)-7

Step-by-step explanation:

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2 years ago

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Write 2x3 − 3x2 + x5 in standard form. What is the classification of this polynomial by its degree? by its number of terms?

andrew-mc [135]

Answer:

x⁵ +2x³ -3x², degree 5, 3 terms

Step-by-step explanation:

We assume you intend your expression to be ...

2x³ -3x² +x⁵

The superscript numbers are exponents. Each indicates the degree of the term. In standard form, terms are listed in decreasing order by degree:

x⁵ +2x³ -3x² . . . . standard form

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2 years ago

Does anyone understand this?. I also have to show my work.

snow_lady [41]

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

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Step-by-step explanation:

Given equation is C= $\frac{5}{9}(F -32)$

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=0.

For F = 41.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(41 -32)$

C=05

For F = 50.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(50 -32)$

C=10

For F = 59.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

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Note: The figure shows a graph of given equation with points.

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C= $\frac{5}{9}(F -32)$

C= $\frac{5}{9}(32 -32)$

C=18.333333.

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C= $\frac{5}{9}(F -32)$

0= $\frac{5}{9}(F -32)$

0= $(F -32)$

F=32 Temperature.

Ans D). Slope of the line C= $\frac{5}{9}(F -32)$

The slope of line is given by s= $\frac{Y1-Y2}{X1-X2}$

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s= $\frac{Y1-Y2}{X1-X2}$

s= $\frac{0-5}{32-41}$

s= $\frac{5}{9}$

Slope of line C= $\frac{5}{9}(F -32)$ is $\frac{5}{9}$

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3 years ago

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UkoKoshka [18]

Answer:

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Step-by-step explanation:

According to the question, we have a right triangle formed by the ladder with the wall and the floor.

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$sin(\theta)=\frac{opposite}{hypotenuse}$

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$sin(\21"27")=\frac{h}{14.5}$

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2 years ago