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tangare [24]
4 years ago
5

Ammonia (NH3) Is base.

Chemistry
1 answer:
miv72 [106K]4 years ago
7 0

Answer:

Ammonia accepts a proton from water

Explanation:

Let us quickly remind ourselves of the Brownstead-Lowry definition of an acid. According to Brownstd-Lowry, an acid is any substance that donates hydrogen ions while a base is any substance that accepts hydrogen ions. The hydrogen ion is also known as a proton.

If we look at the behaviour of ammonia in water;

NH3(g) + H2O(l) ----> NH4^+(aq) + OH^-(aq)

We can easily see that ammonia accepts a proton from water (this makes it a Brownstd-Lowry base) and the hydroxide ion is formed in the process. Water functions as the proton donor here.

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What is the molarity of 10.0 g of NaCl dissolved in water to make 100. mL?
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Answer:

=<em><u> 1.7 M</u></em>

Explanation:

Molecular mass of NaCl = ( 23+35.5 ) = 58.5g

58.5g of NaCl are weighed by 1 mole of NaCl

10.0g of NaCl will be weighed by ( 10÷58.5 )

<em> <u>= 0.17 moles of </u><u>NaCl</u></em>

100mL = ( 100÷1000)L = 0.1L

0.1L of a solution is occupied by 0.17 moles of NaCl

<u>1L</u> of solution will be occupied by [(1÷0.1)×0.17]

=<em><u>1</u></em><em><u>.</u></em><em><u>7</u></em><em><u> </u></em><em><u>M</u></em>

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4 years ago
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Read the given equation. 2Na + 2H2O → 2NaOH + H2
Crank

Answer:

B) 12.9 grams.

Explanation:

How many moles of molecules in that 6.30 L of H₂?

The volume of one mole of an ideal gas at STP (0 °C, 1 atm) is 22.4 liters.

(The volume of that one mole of gas at STP will be 22.7 liters if STP is defined as 0 °C and 10⁵ Pa).

\displaystyle n(\text{H}_2) = \frac{6.30\;\text{L}}{22.4\;\text{L}\cdot\text{mol}^{-1}} = 0.28125\;\text{mol}.

How many moles of Na will be needed?

The coefficient in front of Na in the equation is twice the coefficient in front of H₂. It takes two moles of Na to produce one mole of H₂.

n(\text{Na}) = 2\;n(\text{H}_2) = 2\times 0.28125= 0.5625\;\text{mol}.

What's the mass of that many Na atoms?

Refer to a modern periodic table. The molar mass of ₁₁Na is 22.990. The mass of one mole of Na atoms is 22.990 gram. The mass of 0.5625 moles of Na atoms will be

m = n\cdot M = 0.5625 \times 22.990 = 12.9\;\text{g}.

(2 sig. fig. as in the volume of the H₂ gas.)

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