Answer:
=<em><u> 1.7 M</u></em>
Explanation:
Molecular mass of NaCl = ( 23+35.5 ) = 58.5g
58.5g of NaCl are weighed by 1 mole of NaCl
10.0g of NaCl will be weighed by ( 10÷58.5 )
<em> <u>= 0.17 moles of </u><u>NaCl</u></em>
100mL = ( 100÷1000)L = 0.1L
0.1L of a solution is occupied by 0.17 moles of NaCl
<u>1L</u> of solution will be occupied by [(1÷0.1)×0.17]
=<em><u>1</u></em><em><u>.</u></em><em><u>7</u></em><em><u> </u></em><em><u>M</u></em>
Explanation:
<h2>see the attachment. hope it will help you... </h2>
Answer:
B) 12.9 grams.
Explanation:
How many moles of molecules in that 6.30 L of H₂?
The volume of one mole of an ideal gas at STP (0 °C, 1 atm) is 22.4 liters.
(The volume of that one mole of gas at STP will be 22.7 liters if STP is defined as 0 °C and 10⁵ Pa).
.
How many moles of Na will be needed?
The coefficient in front of Na in the equation is twice the coefficient in front of H₂. It takes two moles of Na to produce one mole of H₂.
.
What's the mass of that many Na atoms?
Refer to a modern periodic table. The molar mass of ₁₁Na is 22.990. The mass of one mole of Na atoms is 22.990 gram. The mass of 0.5625 moles of Na atoms will be
.
(2 sig. fig. as in the volume of the H₂ gas.)
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