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Goryan [66]
4 years ago
13

You are given element x. what should you do to identify the element. (Sains) ​

Chemistry
1 answer:
zhuklara [117]4 years ago
5 0
The simplest way to use the periodic table to identify an element is by looking for the element’s name or elemental symbol. You may also be able to identify it by looking for the element’s atomic number.
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What happens to the atoms in a scoop of ice cream as it melts?
nata0808 [166]

Answer:

C. They vibrate faster.

Explanation:

right on edgenuity.

7 0
3 years ago
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In addition to NF3, two other fluoro derivatives of nitrogen are known: N2F4 and N2F2. What shapes do you predict for these two
sineoko [7]

Answer:

Pyramid trigonal and trigonal planar, respectively.

Explanation:

The shape of a molecule is how the atoms are organized in the space, and it happens to minimize the repulsive force of the bonds and the lone pairs of electrons. Thus, in the molecules given, the two N atoms are the central atoms, because they can do the most number of bonds.

Nitrogen has 5 electrons in the valence shell, so it can do 3 bonds to be stable with 8 (octet rule), and fluorine has 7 electrons in the electron shell, so it can do 1 bond to be stable with 8.

In the molecule of N2F4, the two nitrogen do a simple bond between then, and simple bond with 2 F each, as shown below. So, each nitrogen still has 1 lone pair of electrons. To minimize it, the better shape is the pyramid trigonal.

In the molecule of N2F2, the two nitrogen do a double bond between them, and a simple bond with one F each, as shown below. They still have lone pairs, and the double bond is stiff, so it doesn't rotate. Thus, the trigonal planar shape is the better one.

7 0
3 years ago
1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

5 0
3 years ago
What is the molecular weight of H3PO4
olga2289 [7]
H = 1 amu
P =  31 amu
O = 16 amu

Therefore:

H3PO4 = 1 x 3 + 31 + 16 x 4 => 98 u

hope this helps!
6 0
4 years ago
How many grams of calcium cyanide (Ca(CN)2) are contained in 0.79 mol of calcium cyanide?
Allushta [10]
I dont know but do you know da wae brudda?


3 0
3 years ago
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