Beaker 3 shows a clear chemical reaction.
Answer:
it would do wonders for the health of those using them and, by extracting energy from the fuel more efficiently, would be more environmentally sustainable too.
Given the reaction 2Pb(s)+O2(g)= 2PbO(s) and a reactant amount of 451.4 grams, we are asked for the yield of the reaction. The amount of lead present produces 451.4/207.2 *( 2/2) *(223.2) via 100% conversion, 486.26 grams lead (II) oxide. hence the percent yield is 356.7g /<span>486.26 g or equal to 73.35 percent</span>
Answer:
0%
Explanation:
- The probability that both of the parents are homozygous recessive is zero.
- In our case, The gene for tallness is dominant over the gene for dwarfism
- Therefore; TT is homozygous dominant while tt is homozygous recessive and Tt is heterozygous.
- Heterozygous genotype (Tt) will exhibit a tall phenotype.
- When two parents are crossed and all the offsprings are tall then the possible genotype of the parents is either;
- Homozygous dominant for both parents or
TT x TT
2. One parent is homozygous dominant and the other is homozygous recessive.
TT x Tt
- Therefore, the probability of having both parents as homozygous recessive when all the offspring are tall is Zero.
Answer;
12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.
Explanation:
Using a balanced chemical equation we can identify the number of carbon, hydrogen, and oxygen atoms in sugar.
CxHyOn + 12O₂ → 11 H₂O + 12CO₂
When an equation is completely balanced, then the number of each atom of an element is equal on the reactant side and the product side.
Therefore;
For carbon; x = 12
For Hydrogen; y = (11×2) = 22
For Oxygen; n + (12×2) = 11 + (12×2)
= n + 24 = 11 + 24
n = 11
Therefore the sugar has, 12 carbon atoms, 22 hydrogen atoms and 11 oxygen atoms.
Thus the balanced equation would be;
C₁₂H₂₂O₁₁ + 12O₂ → 11 H₂O + 12CO₂
