The right answer is the first molecule (3-methyl-butan-2-one).
There are many bands around 2900-3000 cm-1 proving the presence de C-H bound.
There an intense band in 1700 cm-1 proving the presence of C=O.
There's no band proving the presence of aromatic structure, C=C bond nor C-N bond.
Answer:
a. 10.54
Explanation:
reaction is
NH₃ + NaOH -----------------NH₄Cl + H₂O
0.10 mol NaOH will consume 0.10 mol NH₃ thereby decreasing the initial amount of moles NH₃ and increasing that of NH₄Cl
mol NH₃ = 0.80 - 010 = .70
mol NH₄Cl = 0.80 + .10 = 0.90
pH = pKₐ + log (( NH₃/NH₄Cl))
pH = 9.26 + log (( 0.90 + 0.70)) = 9.26 + 0.11 = 10.54
Answer: The Eurasian Plate or both the Eurasian and Pacific Plate.
Explanation:
