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Verdich [7]
4 years ago
7

A number, x, rounded to 2 significant figures is 1300Write down the error interval for x.​

Mathematics
1 answer:
Zielflug [23.3K]4 years ago
8 0

Answer:

[1250,1350).

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

It is possible if,

1. The value of x is greater than of equal to 1250 and less than or equal to 1300.

i.e., 1250\leq x\leq 1300     ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

i.e., 1300\leq x       ...(2)

On combining (1) and (2), we get

1250\leq x < 1350

1350 is not included in the error interval for x.​

Interval notation is [1250,1350).

Therefore, the error interval for x is [1250,1350).

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4 years ago
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PLEASE HELP ASAP!!!!! a simulation by tossing a coin to model whether these puppies will be male or female. • Let heads (H) = fe
weeeeeb [17]

Answer:

7/10 or 70%

Step-by-step explanation:

There has to be at least two T in each result of the simulation. This means you can also have 3 T's and 4 T's in the result.

These are the results that qualify as having at least two T's.

1. TTTT, 2. TTTT, 3. THTH, 4. HTTT, 5. TTTT, 7. HTHT, 9. THTH

That is 7 out of the 10 results which is 7/10 or 70%

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2 years ago
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7 0
4 years ago
Which of the following is true regarding the sequence graphed below?
VikaD [51]

Answer:

Option D. The sequence is not arithmetic because the terms do not have a common difference.

Step-by-step explanation:

We are given  points in a graph as:

             x              y         common difference

             1               1    

             2              4            4-1=3

             3               9           9-4=5

             4              16           16-9=7

             5              25          25-16=9

Clearly from the set of values that are given in the graph we could observe that the function that is formed using these set of values is:

y=f(n)=n² where n=1,2,3,4,5,.....

Hence, the following sequence is not an arithmetic sequence as the common difference is different.

( Common difference is the difference in the y-value  from it's preceding y-value)

Hence, option: D is the true option.

D. The sequence is not arithmetic because the terms do not have a common difference.

7 0
3 years ago
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Suppose that the inverse demand for a downstream firm is P = 150 − Q. Its upstream division produces a critical input with costs
kozerog [31]

Answer:

The marginal revenue is MT_d  =   116.66

Step-by-step explanation:

From the question we are told that

    The inverse demand for a downstream firm is  P = 150 -Q

    The cost of the critical input produced by  upstream division is  CU(Q_d) = 5(Q_d)^2

     The cost of the critical input produced by downstream firm  is  Cd(Q) = 10Q

Generally

The marginal revenue of the downstream firm - The marginal cost  of the downstream firm =  Net marginal revenue of downstream

i.e

    MR_d  - MC_d = MT_d

Also  

  The marginal revenue of the downstream firm - The marginal cost  of the downstream firm =  Marginal upstream cost  

       i.e

            MR_d  - MC_d = MC_u

So

     MR_d  - MC_d = MC_u

Generally the total revenue of  downstream firm is mathematically represented as

          TR  =  P *  Q

Here Q stands for quantity produced by the downstream firm  and  TR is the total revenue

         TR  =  [150 - Q] * Q

=>      TR  =  150Q - Q^2

Generally the marginal revenue of the downstream firm is mathematically evaluated as  

         MR_d =\frac{d (TR)}{d Q} =  150 - 2Q

Generally marginal downstream first cost is mathematically evaluated as

         MC_d = \frac{d(Cd(Q)) }{dQ}  =  10

Generally the net marginal revenue of the downstream firm is mathematically represented as

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=>        MT_d  =   140 - 2Q

Generally the marginal upstream cost is mathematically represented a

               MC _u =\frac{d [CU(Q_d)]}{dQ_d}  = 10(Q_d)

Generally  Q_d = Q this because Q_d represents the quantity produced by the downstream firm and also  Q is associated with the cost of the downstream quantity  

So

            MC _u =\frac{d [CU(Q)]}{dQ}  = 10Q

=>         10(Q) =  140 -2Q

=>          Q =  11.67

So the net marginal revenue of the downstream firm is mathematically represented as

=>        MT_d  =   140 - 2(11.67)

=>        MT_d  =   116.66

     

7 0
3 years ago
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