We are given : m∠WYX=(2x−1)° and m∠WYZ=(4x+1)°.
∠WYX and ∠WYZ are complementary.
We know, sum of complementary angles is = 90°.
So, we need to add ∠WYX and ∠WYZ and set it equal to 90°.
m∠WYX + m∠WYZ = 90°.
Plugging values of ∠WYX and ∠WYZ in the above equation, we get
(2x−1)° + (4x+1)° = 90°.
Removing parentheses from both sides,
2x-1 + 4x+1 =90.
Combining like terms,
2x+4x= 6x and -1+1 =0
6x +0 =90.
6x=90.
Dividing both sides by 6.
6x/6 =90/6
x= 15.
Plugging value of x=15.
m∠WYX=(2x−1)° = 2*15 -1 = 30 -1 =29
m∠WYZ=(4x+1)° = 4*15 +1 = 60+1 = 61.
Therefore, ∠WYX=29° and ∠WYZ=61°.
Answer:
x = -6
Step-by-step explanation:

Answer:
30 people ordered apple pie
Step-by-step explanation:
one third of the total people:
180/3 = 60
subtract the people who ordered ice cream, so that we have the total people who ordered pie:
180-60= 120
divide the total people by 4 to find the people who ordered apple pie
120/4 = 30
30 people ordered apple pie
Problem 1
Answer: C) No solution
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Explanation:
We have z = -4 and 4z = -4 at the same time. Solving 4z = -4 leads to z = -1
So in effect we have z = -4 and z = -1 at the same time, but this is a contradiction. A variable can only hold one number at a time.
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Problem 2
Answer: C) Infinitely many solutions
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Explanation:
The two equations are equivalent. You can prove as such by isolating 2y in the first equation.
5x = 8-2y
5x+2y = 8
2y = 8-5x
2y = -5x+8
-5x+8 = 2y
This shows the first equation is equivalent to the second, and vice versa. They both graph the same line. Any point along the line is a solution. So that's why there are infinitely many of them.
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Problem 3
Answer: Choice A) 
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Explanation:
The range is the set of the possible y values. We're concerned with every y coordinate of each (x,y) solution. So we only focus on the shaded region.
The dashed line means we exclude the boundary. It's an electric fence we cannot touch. So y > -6 or -6 < y describes part of the range
The other part is
since y = 3 is the when the highest point occurs.
So writing
describes all possible y values of each (x,y) solution in the shaded region.