Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5
Step-by-step explanation:
Answer:
A) 240 m^3
Step-by-step explanation:
F(x) = ㏑(x² - 4)
Domain: {-2 ≤ x ≤ 2}, or [-2, 2]
Answer:
B. (6, 10)
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 8
Standard deviation = 1
Give an interval that is likely to contain about 95% of the sampled cashiers' hourly wages.
By the Empirical Rule, 95% of the sampled cashiers' hourly wages will be within 2 standard deviations of the mean, so from 2 standard deviations below the mean to two standard deviations above the mean
Two standard deviations below the mean:
8 - 2*1 = 6
Two standard deviations above the mean
8 + 2*1 = 10
So the correct answer is:
B. (6, 10)
