Let's solve this by substitution.
y is given by the 2nd eqn as y = (1/3)x + 7. Subst. (1/3)x + 7 into the first eqn as a replacement for y: x + 9( (1/3)x + 7) = 3.
clear out fractions by mult. all 3 terms by 3: 3x + 9x + 63 = 3
Combine like terms: 12x = -60. Then x = -5
Find y by subst. -5 for x in the 2nd equation: y = (1/3)(-5) + 7
= -5/3 + 35/3 = 30/3 = 10.
Thus, the solution (x,y) of this system is (-5,10).
Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
Answer:
cool
Step-by-step explanation:
Answer:
(5,7,8.6)
Step-by-step explanation:
Create a line on each the x axis and the y axis which intersects at a right triangle. The x axis line is 7 squares and the y axis is 5 squares. Now you can use the Pythagorean theorem.
a^2+b^2=c^2
7^2+5^2=c^2
49+25=c^2
74=c^2
8.6=c
Answer:
Depends on the domain and the graph.
Step-by-step explanation:
