The probability that both of the students are on Team D is about 5.56%
There are 4 teams, so the first person has a 1/4 chance of being on Team D.
However, for the second person, there are only 6 spots left out of 27 to be on Team D.
To find the combined probability, we need to multiply the two fractions.
1/4 times 6/27 = 1/18 or about 5.56%
37.5% i believe! i’m not reallt sure if this is correct; but i believe it is. hope this helps!
65 miles per hour
feet in a mile: 5,280 ft
65 divided by 60= 1.08 miles per minute
22 x 1.08 = 23.76 miles
23.76 mi x 5,280 ft = 125,452.8 ft in 22 minutes
Answer:
yes because of a postulate or a theorem
Step-by-step explanation:
Answer:
QR=8
QU=76
Measure of arc ST=114°
Measure of arc QR=114°
Measure of arc XT=57°
Step-by-step explanation:
Given
YU=YV
ST=16
mQS=34
mRT=98
Using Pythagoras theorem,
QR=8
QU=76
QR=ST
So they both span the same arc.
Let the arc=x
360 - QS - RT = QR + ST
Recall QR=ST
360 - 34 - 98 = x + x
228 = 2x
X=228/2
X=114°
Therefore, measure of arc ST and arc QR=114° each
Measure of the span of arc XT = (1/2) of (arc ST)
= (1/2)(114°)
= 57°
