Technician B only is right, who says that to avoid warping the cylinder head, the engine must be cold before removing it.
<h3>What is the cylinder head doing in my car?</h3>
The main task of the cylinder head is to close the discharge chamber of the engine from the top. The upper part of the engine is reached the cylinder head, while the lower part is the engine partnership.
The cylinder head sits on the engine and shuts off the combustion chamber. The gap that remains between the cylinder head and the engine is achieved by the head gasket.
<h3>How to recognize signs of possible defects</h3>
If you notice abnormalities in the functioning of your engine, it is advisable to contact a garage as soon as feasible to prevent further injury.
- The signs of cylinder head flaws include:
- You notice a power loss of the machine
- The cooling water temperature is in the red area
- You see oil in the cooling water
- You must supply water and oil after just a short time
- You notice a bad cold start behavior
To learn more about the cylinder, refer
brainly.com/question/23935577
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complete question is,
Technician A only
Technician B only
Both A and B
Neither A nor B
Answer:
23.34 seconds
Explanation:
Flow rate = 1500
Arrival = 800 vehicle per hour
Cycle c = 60 seconds
Dissipation time = 10 seconds
Arrival time = 800/3600 = 0.2222
Rate of departure = 1500/3600 = 0.4167
Traffic density p = 0.2222/0.4167 = 0.5332
Real time = r
r + to + 10 = c
to = c-r-10 ----1
t0 = p*r/1-p ----2
Equate both 1 and 2
C-r-10 = p*r/1-p
60-r-10 = 0.5332r/1-0.5332
50-r = 0.5332r/0.4668
50-r = 1.1422r
50 = 1.1422r + r
50 = 2.1422r
r = 50/2.1422
r = 23.34 seconds
Answer:
Pitch circle diameter = 5,66 inch
Explanation:
<u>According to the pitch circle diameter formula</u>
<em>Dc= Dp - 2b</em> ; where Dp= primitive diameter, b= dedendum of the tooth and also the dedendum formula is b= 1,25 Pc/π.
The definition of primitive diameter is equal to (Pc*Z)/π ; Pc= circular pitch and Z= number of teeths.
<u>Replacing in the formula </u>
⇒ Dc= (Pc*Z)/π - 2* 1,25 Pc/π, Pc= 0,375 ; Z=50
In conclusion the pitch circle diameter is equal to:
Dc= 5,66 inch.
<h3> </h3>
Answer:
1211 N.
Explanation:
Okay, we are given the following data or parameters or information in the question above;
=> "aluminum (E = 70 GPa) tube of length 8-m.
=> "The aluminum is used as a simply supported column carrying a 1.2 kN axial load"
The axial load to provide a factor of safety of 2 against buckling =[ (22/7)^2 × 224348 × 1000 × 70] ÷ (8 × 1000)^2 × 2.
The axial load to provide a factor of safety of 2 against buckling = 1211 N.