Answer:
a) isentropic efficiency = 84.905%
b) rate of entropy generation = .341 kj/(kg.k)
Please kindly see explaination and attachment.
Explanation:
a) isentropic efficiency = 84.905%
b) rate of entropy generation = .341 kj/(kg.k)
The Isentropic efficiency of a turbine is a comparison of the actual power output with the Isentropic case.
Entropy can be defined as the thermodynamic quantity representing the unavailability of a system's thermal energy for conversion into mechanical work, often interpreted as the degree of disorder or randomness in the system.
Please refer to attachment for step by step solution of the question.
T1=T2=500°C
<u>Explanation:</u>
Given-
Pressure, P1 = 500 bar
Temperature, T1 = 500°C
P2 = 1 bar
T2 after expansion, = ?
We know,
P1/T1 = P2/T2
500/ 500 = 1/T2
T2 = 1°C
If the steam were replaced by an ideal gas, since enthalpy of ideal gas is a function of temperature only, we easily obtain T2 = T1 = 500°C
Answer:
1.4 psi
Explanation:
Before diving into the solution to the question above, let's pick out the parameters needed in solving this problem from the question.
=> The measurement for the outer diameter of the balloon = 20 inches, the measurement for the thickness = 0.012 in, the allowable tensile stress = 1ksi and the allowable shear stress in the balloon = 0.3 ksi.
The first thing to determine is the inner diameter = 20 - 2 × 0.012 in = 19.976 in.
Therefore, the tensile stress:
1000 = k × [19.976/2]÷ 2 × 0.012 = 2.4 psi.
Also, the sheer stress which is also the maximum permissible pressure in the balloon can be calculated below as:
0.3 × 1000 = k × [19.976/2]/ 4 × 0.012 = 1.4 psi.