Answer:
1. You have the courage to help without expecting a reward.
2. Because actions are more eloquent than words. Actions are far more valuable and counted than words, and that's how she inspired me.
3. Doing simple things that can make someone grateful and happy without knowing that someone is inspired and motivated by your good deeds, and also doing some interesting things By.
Explanation:
Answer:
The answer is "
"
Explanation:
Air flowing into the
Flow rate of the mass 
inlet temperature 
Pipeline
Its air is modelled as an ideal gas Apply the ideum gas rule to the air to calcule the basic volume v:
Friction losses in pipes can be reduced by decreasing the length of the pipes, reducing the surface roughness of the pipes, and increasing the pipe diameter. Thus, options (c),(e), and (f) hold correct answers.
Friction loss is a measure of the amount of energy a piping system loses because flowing fluids meet resistance. As fluids flow through the pipes, they carry energy with them. Unfortunately, whenever there is resistance to the flow rate, it diverts fluids, and energy escapes. These opposing forces result in friction loss in pipes.
Friction loss in pipes can decrease the efficiency of the functions of pipes. These are a few ways by which friction loss in pipes can be reduced and the efficiency of the piping system can be boosted:
- <u><em>Decrease the length of the pipes</em></u>: By decreasing pipe lengths and avoiding the use of sharp turns, fittings, and tees, whenever possible result in a more natural path for fluids to flow.
- <u><em>Reduce the surface roughness of the pipes</em></u>: By reducing the interior surface roughness of pipes, a smooth and clearer path is provided for liquids to flow.
- <u><em>Increase the pipe diameter: </em></u>By widening the diameters of pipes, it is ensured that fluids squeeze through pipes easily.
You can learn more about friction losses at
brainly.com/question/13348561
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Answer & Explanation:
(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 2
= 12 Hz
2fs + fm = 2 * 10 + 2
= 22 Hz
3fs + fm = 3 * 10 + 2
= 32 Hz
4fs + fm = 4 * 10 + 2
= 42 Hz
Subtracting:
fs - fm = 10 - 2
= 8 Hz
2fs - fm = 2 * 10 - 2
= 18 Hz
3fs - fm = 3 * 10 - 2
= 28 Hz
4fs - fm = 4 * 10 - 2
= 38 Hz
5fs - fm = 5 * 10 - 2
= 48 Hz
(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination
The sampling rate is 10Hz
List of all the frequencies present in the output that are less than 50Hz.
Adding:
fs + fm = 10 + 8
= 18 Hz
2fs + fm = 2 * 10 + 8
= 28 Hz
3fs + fm = 3 * 10 + 8
= 38 Hz
Subtracting:
fs - fm = 10 - 8
= 2 Hz
2fs - fm = 2 * 10 - 8
= 12 Hz
3fs - fm = 3 * 10 - 8
= 22 Hz
4fs - fm = 4 * 10 - 8
= 32 Hz
5fs - fm = 5 * 10 - 8
= 42 Hz
