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3 years ago

Which is the area of a rectangle with a length of 21 feet and a width of 15 feet?

Mathematics

2 answers:

nexus9112 [7]3 years ago

8 0

Answer:

315 ft ²

Step-by-step explanation:

The formula for the area of a rectangle is Area=Length × Width

Area=21×15

Area=315 ft ²

MA_775_DIABLO [31]3 years ago

3 0

Answer:

315

Step-by-step explanation:

Area = Length x Width

Area = 21 x 15

Area = 315

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Please please help. Marking Brilliant for the correct answer

NISA [10]

Answer:

x = 19

Step-by-step explanation:

(whole secant) x (external part) = (tangent)^2

(x-7+4) * 4 = 8^2

(x-3)*4 = 64

Divide each side by 4

x-3 =16

Add 3 to each side

x-3+3 = 16+3

x = 19

5 0

3 years ago

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

Ratios

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago

10(a-2.5+0.56b) is this equivalent to 10a - 25+56b

kirill115 [55]

Hey there!

10(a - 2.5 + 0.56b)

= 10(a) + 10(-2.5) + 10(0.56b)

= 10a - 25 + 5.6b

= 10a + 5.6b - 25

Therefore, your answer is: 10a + 5.6b - 25

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0

3 years ago

HELPPPP If y=4, 3y+6=7(2y-3)

Step2247 [10]

Answer:

i think your question is missing something??

Step-by-step explanation:

3(4) + 6 = 7 (2(4)-3)

12 + 6 = 7 (8-3)

18 = 7 (5)

18 = 35?

8 0

3 years ago

Find the area of r = 4.5

Gnom [1K]

here ya go 14.13m2 A≈14.13⁢m2

6 0

3 years ago