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andreyandreev [35.5K]
3 years ago
8

Determine the intercepts of the line.

Mathematics
1 answer:
lbvjy [14]3 years ago
6 0
The x is (3,0) and the y is (0,-10)
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Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

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3 years ago
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Find three consecutive odd integers whose sum is 13 more than twice the largest of the three intergers
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15,17,19 
Suppose the three odd integers are #n#, #n+2# and #n+4# 
Their sum is: 
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#13# more than twice the largest of the three is: 
#2(n+4)+13 = 2n+21# 
From what we are told these two are equal: 
#3n+6 = 2n+21# 
Subtract #2n+6# from both sides to get: 
#n = 15# 
So the three integers are: 
#15, 17, 19#
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3 years ago
Can someone explain? Brainliest + Points! :D
Ulleksa [173]
I'm not I understand. The range is the highest value minus the lowest value, which on the graph is 10-4=6.
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Answer choices are <br> y-x=-4<br> y-x=-2<br> y-4=x<br> y+4x=1
ycow [4]

Answer:

Y+4x=1

Step-by-step explanation:

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