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hram777 [196]
3 years ago
7

SOMEONE PLEASE HELP ME ASAP PLEASEEE!!!!!!!!

Mathematics
2 answers:
kirill [66]3 years ago
6 0
Plug in the values of the variables [ (2+5)-2x2 ] then add what’s in the parenthesis [ 7-2x2 ] and then multiply [ 7-4 ] and subtract so your answer would be 3
ahrayia [7]3 years ago
5 0

Answer:

3

Step-by-step explanation:

x=5 and y=2, so we just have to plug them into the equation.

(2+5)-2(2)

7-4

7-4=3

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What is the total amount of 2/5+5/3+9/3 and the lowest common denominator?
gregori [183]

The lowest common denominator is lcm(5, 3), which is 15.

The sum of 2/5 + 5/3 + 9/3 is 6/15 + 25/15 + 45/15, which is 76/15 or 5\frac{1}{15}.

4 0
3 years ago
Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What
Flauer [41]

Answer:

31^8

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

6 0
4 years ago
Cassandra wants to solve the equation 30=2/5p.Whta operation should she perform to isolate the variable?
frosja888 [35]
Well, if you want to get p by itself, you will have to multiply both sides by 5/2. 2/5 times 5/2 gives you 1p, or just p. 
4 0
3 years ago
Read 2 more answers
The length of a rectangle is twice the width. Find the width if the perimeter is 60 centimeters. Define a variable, write an equ
-Dominant- [34]

width = w

length = 2w

perimeter = 2w + 2 l

perimeter = 2w +2(2w)

60 = 2w + 4w

60= 6w

60=6w

w = 60/6 = 10

length = 10x2 = 20

10+10+20+20 = 60

3 0
4 years ago
Read 2 more answers
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
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