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cestrela7 [59]
3 years ago
11

The smallest whole number by which 9408 must be divided to get perfect square number

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

9408,Is the only number that can divide into the same number to get exactly down to 1.

Step-by-step explanation:

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Igneous rock that cools slowly will have what type of mineral grains??
daser333 [38]
I think it would have crystal formations if I remember correctly.
7 0
3 years ago
Write the multiple of the first even number from 11 to 20​
andrew-mc [135]

Answer:

Multiples [10] - 10, 20, 30, 40, 50

Multiples [11] - 11, 22, 33, 44, and 55

<u><em>Find the Even numbers of these multiples</em></u>

Multiples [10]

  • - 10 = Even
  • - 20 = Even
  • - 30 = Not Even
  • - 40 = Even
  • - 50 = Not Even

  1. <u><em>10 × 1 = 10</em></u>
  2. <u><em>10 × 2 = 20</em></u>
  3. <u><em>10 × 3 = 30</em></u>
  4. <u><em>10 × 4 = 40</em></u>
  5. <u><em>10 × 5 = 50</em></u>

Multiples [11]

  • - 11 = Not Even
  • - 22 = Even
  • - 33 = Not Even
  • - 44 = Even
  • - 55 =  Not Even

  1. <u><em>    11 × 1 = 11</em></u>
  2. <u><em>    11 × 2 = 22</em></u>
  3. <u><em>    11 × 3 = 33</em></u>
  4. <u><em>    11 × 4 = 44</em></u>
  5. <u><em>    11 × 5 = 55</em></u>
  6. <u><em>    11 × 6 = 66</em></u>
  7. <u><em>    11 × 7 = 77</em></u>
  8. <u><em>    11 × 8 = 88</em></u>
  9. <u><em>    11 × 9 = 99</em></u>

Step-by-step explanation:

.... I messed up, sorry. I thought that 20 said 11

8 0
2 years ago
A gumball is approximately spherical and has a diameter of 1 inch. What is the approximate volume of the gumball? A gumball is a
KatRina [158]

The approximate volume of the spherical gumball is: C. 0.5236 in.³.

<h3>How to Determine the Volume of a Spherical Shape?</h3>

If a shape is spherical, it means it has a shape of a sphere. To determine the volume of the spherical shape, we would use the formula for the volume of a sphere, which is given as:

Volume of a sphere = 4/3 × π × r³, where r (radius of the sphere) is half of the diameter of the sphere.

Given the following parameters of the sphere as:

Diameter of sphere = 1 inch.

Radius (r) = 1/2(1) = 0.5 inch.

π = 3.14

To find the approximate volume of the spherical gumball, substitute the value of r into 4/3 × π × r³:

Volume of the spherical gumball = 4/3 × 3.14 × 0.5³

Volume of the spherical gumball = 4/3 × 3.14 × 0.125

Volume of the spherical gumball = (4 × 3.14 × 0.125)/3

Volume of the spherical gumball = (1.57)/3

Volume of the spherical gumball = 0.523 in.³

Therefore, we can conclude that the approximate volume of the spherical gumball is: C. 0.5236 in.³.

Learn more about volume of sphere on:

brainly.com/question/22807400

#SPJ1

5 0
2 years ago
Evalute costheta if sintheta = (sqrt5)/3
torisob [31]

Answer:

\large\boxed{\cos\theta=\pm\dfrac{2}{3}}

Step-by-step explanation:

Use \sin^2x+\cos^2x=1.

We have

\sin\theta=\dfrac{\sqrt5}{3}

Substitute:

\left(\dfrac{\sqrt5}{3}\right)^2+\cos^2\theta=1\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(\sqrt5)^2}{3^2}+\cos^2\theta=1\qquad\text{use}\ (\sqrt{a})^2=a\\\\\dfrac{5}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{5}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{9}{9}-\dfrac{5}{9}\\\\\cos^2\theta=\dfrac{4}{9}\to \cos\theta=\pm\sqrt{\dfrac{4}{9}}\\\\\cos\theta=\pm\dfrac{\sqrt4}{\sqrt9}\\\\\cos\theta=\pm\dfrac{2}{3}

3 0
3 years ago
Read 2 more answers
I need help with this question
Svetlanka [38]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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