This problem tackles the place values of numbers. From the rightmost end of the number to the leftmost side, these place values are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions, ten millions, one hundred millions, and so on and so forth. My idea for the solution of this problem is to add up all like multiples. In this problem, there are 5 multiples expressed in ones, thousands, hundred thousands, tens and hundreds. Hence, you will add up 5 like terms. The solution is as follows

30(1) + 82(1,000) + 4(100,000) + 60(10) + 100(100)

The total answer is 492,630. Therefore, the number's identity is 492,630.

7 0

2 years ago

jeromes rain gauge showed 13 9/10 centimeters at the end of last month. at the end of this month, the rain gauge showed 15 3/10

Ne4ueva [31]

It rained 1 and 4/10 centimeters. You have to first figure out what adds up to 14, which is 1/10. Then you add 1 to get 15 and 3/10 to get 15 3/10.

3 0

3 years ago

In a class 30 students,20 students like to play cricket and 15 like to play valleyball. Also each student like to play at least

Alisiya [41]

Answer:

Well we add together 20+15 which is 35 which is 5 over the 30 in the class so that means out of the 30 students 5 of them like both games

Hope This Helps