An amateur radio operator erects a 75-foot vertical tower for an antenna. A 117 guy wire is pulled from the top of the tower dia
gonally to the ground. What angle does the wire make with the ground, to the nearest tenth of a degree?
1 answer:
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The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
1 & 2 = Right Triangles
3 & 4 = Not Right Triangles
Step-by-step explanation:
Solved Using Pythagorean Theorem:
1) = 225
= 225
2) = 1521
= 1521
3) = 776
= 784
4) = 244
= 256