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3 years ago

(a + b )(a 2 - ab + b 2)

Mathematics

2 answers:

AleksandrR [38]3 years ago

8 0

Answer:

I think this is it

liubo4ka [24]3 years ago

3 0

Answer:

$a^3+b^3$

Step-by-step explanation:

$(a+b)(a^2-ab+b^2)= a^3-a^2b+ab^2+ba^2-ab^2+b^3=a^3+b^3$

Hope this helps!

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Which rational expression is equal to a positive whole number when evaluated? A.)2^1/2

Angelina_Jolie [31]

I'm going to go with A. but I'm not possitive I'm sorry if that's wrong.

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3 years ago

A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa

UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so $\mu = \frac{14}{60} = 0.2333$

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081$

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0

3 years ago

Currently, Nora is 3 time as old as damon. In 8 years she will be only 2 time as old as Damon. How old will Damon will be in 8 y

Ann [662]

In 8 years Damon will be 16 year's old.

We have Nora who 3 time as old as Damon and in 8 years she will be only 2 time as old as Damon.

We have to determine how old will Damon be in 8 years.

<h3>If your present age is x and your sister is 4 years elder than you. Than what will be her age after 5 years from now.</h3>

Your present age = x.

Hence, your sister's present age = x + 4.

After five years, your age = x + 5.

Hence, your sister's age will be = x + 9.

According to question, we have -

Assume that the present age of Damon is x.

Then, Nora's age will be = y = 3x.

After 8 years -

Damon's age = x + 8

Nora's age = 3x + 8

Therefore -

3x + 8 = 2(x + 8)

3x + 8 = 2x + 16

x = 8

Hence, in 8 years Damon will be = 8 + 8 = 16 year's old.

To solve more questions on Age determination, visit the link below -

brainly.com/question/14580151

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6 0

1 year ago

Find the output, d, when the input, t, is 11. <br><br><br> d = -20+11t<br><br> d= __

mafiozo [28]

Substitute the given value into the equation

-20 + 11*11

Using BODMAS, you do 11*11 first, which is 121

-20+121

Which is 101

Therefore, d is equal lot 101

4 0

3 years ago

Read 2 more answers

Translate "a number is at least 32" into an inequality.

tino4ka555 [31]

Answer:

x $\geq$ 32