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Reika [66]
3 years ago
9

John was experimenting with non-symmetrical designs for kite flying. Suppose he wants to build a flying kite based on the model

below. Provide possible values for segment lengths a, b, c, d, and e in the figure below and explain your reasoning.

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

d=3,e=4,a=5,b=12,c=13

Step-by-step explanation:

a,e,d are a part of a right trianges,3,4,5are pythogorean triplets

also 5,12,13 are pythogorean triplets

hope this helps

plzz mark me brainliest

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Find the percent one number is of another ?
melamori03 [73]

Answer:


Step-by-step explanation:


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4 years ago
-21+2(3-15)-(-3)(+7)+(-3)(-8)​
Alexxx [7]

Answer:

- 21 + 2(3 - 15) - ( - 3)( + 7) + ( - 3)( - 8) \\  =  - 21 - 24 + 21 + 24 \\  = 0

8 0
3 years ago
Elena’s bedroom door is 0.8 meters wide How wide should the door be on the drawing (in cm). Explain how you know. The scale is 1
Vesnalui [34]

Answer:

The door should be 1.6cm wide on the drawing.

Step-by-step explanation:

1 meter is 100 centimeters.

Elena's bedroom door is 80 centimeters wide.

To find how wide it should be on the drawing, divide by 50.

\frac{80}{50} = 1.6cm

The door should be 1.6cm wide on the drawing.

8 0
3 years ago
Read 2 more answers
Five angles of a hexagon measure 119, 129, 104, 139, and 95. What is the measure of the sixth angle?
SIZIF [17.4K]

Answer:

134°

Step-by-step explanation:

The sum of interior angles of a regular polygon is: (n - 2)180

Hexagon has six sides, n is 6

Sum of it's angles is (6 - 2)180 = 720

sum of our hexagon:

119 + 129 + 104 + 139 + 95 + x = 720°

x is 134°

8 0
4 years ago
The average weight of a package of rolled oats is supposed to be at most 18 ounces. A sample of 18 packages shows a mean of 18.2
Radda [10]

Answer:

Pvalue of 0.0446 < 0.05, which means that we reject the null hypothesis and accept the alternative hypothesis, that the true mean is larger than the specification.

Step-by-step explanation:

The average weight of a package of rolled oats is supposed to be at most 18 ounces.

This means that the null hypothesis is:

H_{0}: \mu \leq 18

Is the true mean larger than the specification?

Due to the question asked, the alternate hypothesis is:

H_{a}: \mu > 18

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

18 is tested at the null hypothesis:

This means that \mu = 18

A sample of 18 packages shows a mean of 18.20 ounces with a sample standard deviation of 0.50 ounces.

This means that n = 18, X = 18.2, \sigma = 0.5

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{18.2 - 18}{\frac{0.5}{\sqrt{18}}}

z = 1.7

Pvalue of the test:

Probability of finding a sample mean above 18.2, which is 1 subtracted by the pvalue of z = 1.7.

Looking at the z-table, z = 1.7 has a pvalue of 0.9554.

1 - 0.9554 = 0.0446

0.0446 < 0.05, which means that we reject the null hypothesis and accept the alternative hypothesis, that the true mean is larger than the specification.

5 0
3 years ago
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