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galben [10]
3 years ago
10

Which of the expressions are equivalent to the one below? Check all that apply. (8 + 2) • 4 + 2

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Answer:

is there supposed to be answers to the question?

Step-by-step explanation:

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Hello again. Can someone please help me with this as well. I'll give 100 points!
Aleks04 [339]

Answer: Come on, don’t people learn these things in school!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If f(x)=-16x + 70x + 5, what is f(3)?
Svetach [21]
Answer :
F(3)=-16(3)+70(3)+5
F(3)= 167
, check using your calculator
4 0
3 years ago
Read 2 more answers
The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
3 years ago
Find the ratio of shaded portions to unshaded portions in fig 8.1​
masha68 [24]
15:33

(Mark me the brainliest)
4 0
2 years ago
How do I find the median for a congruent triangle
Andrej [43]
The length of a median is equal to half the square root of the difference of twice the sum of the squares of the two sides of the triangle that include the vertex the mediam is drawn from and the square of the side of the triangle the median is drawn to.

triangle sides by a, b, c.

ma=122c2+2b2−a2

mb=122c2+2a2−b2

mc=122a2+2b2−c2

3 0
3 years ago
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