Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
62.5/100 and 0.625 are both equivalent.
- 1 1/10 + (-1 2/5)
- 1 1/10 + (-1 4/5)
-2 5/10
-2 1/2
Answer:
The answer for the first picture is 84
The answer for the second picture is 36
Step-by-step explanation:
The first triangle is a isosceles triangle which means that two angle lengths must be the same. We use the only angle measurement which is 48 and subtract it from 180 twice because there are two angles lengths that are the same, once we subtract from 180 we have 84. The same process is followed for the second triangle.
180-48-48=84
Second Triangle:
180-72-72=36
