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3 years ago

9

a fully inflated car tire loses 2% of its air every day. if the tire atarted with 4460 cubic feet of air, write an equation to s

how how much air it had after d days.

1 answer:

Trava [24]3 years ago

7 0

Answer:

Step-by-step explanation:

4460=d*2

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The size your dog and the number of times you take it to the vet, The amount your drive to school and the amount you have to pay

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Negative, i think

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2 years ago

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Compare the values of the 2s and 5s in 55,220

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55,220
is fifty five thousand,
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The three consecutive terms

Studentka2010 [4]

Answer:

<h3>1</h3>

Step-by-step explanation:

The nth term of an exponential sequence is expressed as ar^n-1

The nth term of a linear sequence is expressed as Tn = a + (n-1)d

a is the first term

r is the common ratio

d is the common difference

n is the number of terms

Let the three consecutive terms of an exponential sequence be a/r, a and ar

second term of a linear sequence = a +d

third term of a linear sequence = a + 2d

sixth term of a linear sequence = a + 5d

Now if the three consecutive terms of an exponential sequence are the second third and sixth terms of a linear sequence, this is expressed as;

a/r = a + d ..... 1

a = a + 2d ..... 2

ar = a+ 5d .... 3

From 2: a = a + 2d

a-a= 2d

0 = 2d

d = 0/2

d = 0

Substitute d = 0 into equation 1:

From 1: a/r = a + d

a/r = a+0

a/r = a

Cross multiply

a = ar

a/a = r

1 = r

Rearrange

r = 1

<em>Hence the common ratio of the exponential sequence is 1</em>

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3 years ago

A plane has an altitude of 23760 feet which expression can I use to find the altitude in miles

Lyrx [107]

Perhaps we can treat this as a "distance to horizon" problem, the observer is 7 mi above the earth

One formula is: d+=+sqrt%28%283h%29%2F2%29 where d is in miles and h is in feet

Change 7 mi; 5280*7 = 36960 ft

so we have

d = sqrt%28%283960%2A3%29%2F2%29

d ~ 235.5 mi

looking in opposite directions a total of 2*235 = 471 mi can be viewed

Find the circumference of the earth

C = pi%2A8000

C = 25133 mi

:

The arc: 471%2F25133 * 360 = 6.7 degrees

:

This should be pretty close, because the earth is so large compared to the altitude. would appreciate if it you would let me know. C

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3 years ago

Assume that females have pulse rates that are normally distributed with a mean of mu equals 72.0 beats per minute and a standard

ziro4ka [17]

Answer:

a) $P(X$

b) $P(\bar X$

And using a calculator, excel ir the normal standard table we have that:

$P(Z$

c) Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the female pulse rates of a population, and for this case we know the distribution for X is given by:

$X \sim N(72,12.5)$

Where $\mu=72$ and $\sigma=12.5$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

Part b

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

The new z score is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$P(\bar X$

And using a calculator, excel ir the normal standard table we have that:

$P(Z$

Part c

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

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3 years ago