I need to see more of the picture
f(x) = x^3 + x^2 + 3x^0 is neither even nor odd. Why? Because we have a mixture of even and odd powers of x here: x^3 (odd) and x^2 and x^0 (even).
Even functions: all component functions are even (e. g., x^2 and x^0).
Odd functions: all component functions are odd (e. g., x^5 and x^3.
Neither: There's a mixture of even ad odd functions.
Another way to test for even, odd or neither:
Even functions: f(-x) = f(x). Changing the sign of the input (x) doesn't change the sign of the output.
Odd functions: f(-x) = -f(x). Changing the sign of the input changes the sign of the output.
B = 2 · A/h
b = 2 / 1 x 90 / 5 5/8 top times top, bottom times bottom (2 x 90, 1 x 5 5/8)
b = 180 / 5 5/8
b = 32
CHECK ANSWER BY INPUTTING AREA EQUATION AND FILL IN NUMBERS
A = height x base
----------------------
2
Answer:
No
Step-by-step explanation:
cost=25+8d
To be proportional you'd have to have no flat fee: cost=8d
1 day = $8
2 days = $16
5 days = $40
10 days = $80, etc.
I hope I helped.
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;
)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤
)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!