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levacccp [35]
3 years ago
12

I NEED ANSWERS FAST Laura bought 8 3/10 yd of ribbon. She used 1 ⅖ yd to tie a package and 2 ⅓ yd to make a bow. Joe later gave

her 4 ⅗ yd. How much ribbon does she have now? can you put it simple tho
Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

9 1/6 yd

Step-by-step explanation:

First, list the lengths of ribbon Laura had or acquired:

8 3/10 yd + 4 3/5 yd.  This is equivalent to 8 3/10 yd + 4 6/10 yd, or

12 9/10 yd.

Next, list the lengths of ribbon Laura used:

1 2/5 yd + 2 1/3 yd.  The LCD here is 15, so we have 1 6/15 yd + 2 5/15 yd.

Summing up, we get 3 11/15 yd.

Subtract this length from the original 12 9/10 yard with which Laura began:

12 9/10 yd     or    12 27/30 yd (LCD is 30)

- 3 11/15 yd      or   -3 22/30 yd

Subtracting the latter two quantities, we get 9 5/30 yd, or 9 1/6 yd

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