The answer is 10110
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Explanation:
Divide 22 over 2. Use long division to find the quotient and remainder
22/2 = 11 remainder 0 <<--- this remainder will be used later. Call it A, so A = 0
Now repeat for the value 11, which was the quotient above
11/2 = 5 remainder 1 <<--- this remainder will be used later. Call it B, so B = 1
Repeat again for the quotient we just got
5/2 = 2 remainder 1 <<--- this remainder will be used later. Call it C, so C = 1
Repeat again
2/2 = 1 remainder 0 <<--- this remainder will be used later. Call it D, so D = 0
Repeat again
1/2 = 0 remainder 1 <<--- this remainder will be used later. Call it E, so E = 1
The last quotient above is 0, so we stop here. If we tried to keep going, then we'd get nothing but 0 remainders forever.
The remainders we got above were:
A = 0
B = 1
C = 1
D = 0
E = 1
The idea is to read the remainders in reverse order in which we found. So we start with E and work back to A
E = 1
D = 0
C = 1
B = 1
A = 0
So 22 base 10 = 10110 base 2
Answer:
The answer to your question is 13 u²
Step-by-step explanation:
We know that the small triangle is surrounded by right triangles so we can use the Pythagorean theorem to find the lengths of the small triangle
AD² = 3² + 2²
Simplify
AD² = 9 + 4
AD² = 13
AD = 
Find the area of the square
Area = side x side
Area = AD x AD
Area = 
Area = 13 u²
It would be < and > ........
