GF = GH
<F = <H
<E=<G
or
<EGF = <HGJ
answer
<span>e) AAS
</span><span>d) ASA</span>
Check the picture below.
recall the ambiguous SSA case, as the "12" side moves, it ends up with two supplementary angles on the base.
Answer:
Your answer is D
Step-by-step explanation:
First you find which graph has a plot at (4,7) Which the only one with that is D
Then you find (-2,-5). D, again, is the only one with that.
Lastly you find (0,9). D is, again, the only one who has that.
Answer:
Answer:
53/12+28/3=13/34
Solution with Steps
53/12+28/3=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(53/12, 28/3) = 12
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(53/12×1/1)+(28/3×4/4)=?
Complete the multiplication and the equation becomes
53/12+112/12=?
The two fractions now have like denominators so you can add the numerators.
Then:
53+112/12=165/12
This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 165 and 12 using
GCF(165,12) = 3
165÷3/12÷3=55/4
The fraction
55/4
is the same as
55÷4
Convert to a mixed number using
long division for 55 ÷ 4 = 13R3, so
55/4=13 3/4
Therefore:
53/12+28/3=13/34
Solution by Formulas
Apply the fractions formula for addition, to
53/12+28/3
Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(495,36) = 9
49/5÷93/6÷9=554
Convert to a mixed number using
long division for 55 ÷ 4 = 13 R3, so
554=1334
Therefore:
53/12+28/3=13 3/4
So I Believe 13 3/4 or 55/4
I hope this isn't wrong.
Answer:
Step-by-step explanation:
Quality management Excellent Good Fair Total
Excellent 40 25 5 70
Good 35 35 10 80
Fair 25 10 15 50
Total 100 70 30 200
The null and alternative hypothesis:
The expected value is calculated by using the formula:
After using the formula to calculate the table above; we have:
The expected values of the data to be:
Quality management Excellent Good Fair Total
Excellent 35 24.5 10.5 70
Good 40 28 1.2 80
Fair 25 17.5 7.5 50
Total 100 70 30 200
Degree of freedom = ( row - 1 ) × ( column -1 )
Decision rule: To reject the 
if the p-value is less than the ∝
Conclusion: We reject the and conclude that quality management and reputation are not independent.
(B)
