Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms (
) = 250
or, ![\frac{n}{2} [{2a+(n-1)d}] = 250](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B%7B2a%2B%28n-1%29d%7D%5D%20%3D%20250)
or, ![\frac{5}{2} [2*10 + 4d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%5B2%2A10%20%2B%204d%5D%3D250)
or, ![\frac{5}{2} * 4[5+d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%2A%204%5B5%2Bd%5D%3D250)
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
Answer:
Step-by-step explanation:
The distance formula states that the distance between two points 
and 
is 
.
The two points we have are 
and 
. Plugging these numbers into the distance formula, we have
.
Simplifying with order of operations, first using the distributive property, gives
.
Squaring and adding gives
which is the answer in simplest form. This also rounds to about 12.04.
X + 9 = 2x - 3
<u>-x -x </u>
9 = x - 3
<u> +3 +3</u>
12 = x
Number 6 the y intercept is 50 because that’s the point where it crosses the y axis and 7 I believe it would be D= 200
9, 14, and 22.
The formula for checking if a triangle will work is side a + side b > side c.
The only one that works is 9, 14, and 22.
