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masya89 [10]
3 years ago
11

The surface of the moon always looks the same because the moon has no:

Physics
1 answer:
Anestetic [448]3 years ago
8 0
Running water sry if you get it wrong
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What type of power plant burns material to make electricity?
Alecsey [184]
<h2>Hello!</h2>

The answer is: D. Coal

<h2>Why?</h2>

Coal power plants burn coal in to get steam, the steam flows into a turbine which is coupled to an electrical generator.

Coal power plants work burning high amounts of coal into a boiler, generation a lot of steam under extreme pressures. The steam is obtained when the water is heated by the burning coal, then the steam is cooled, being transformed in liquid water again (due the condensation process) and it's sent back on a cyclical process.

Have a nice day!

6 0
3 years ago
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True or false: When an object becomes polarized, it acquires a charge and becomes a charged object.​
PSYCHO15rus [73]

Answer:

i think its true

Explanation:

8 0
3 years ago
How would I graph the data in the table on the graph? ********WORTH 50 POINTS********WILL MARK BRAINLIEST**********
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Answer:

Save the file and try to put stuff over the file. (kinda off like a picture)

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3 years ago
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The Moon and Earth rotate about their common center of mass, which is located about RcM 4700 km from the center of Earth. (This
erica [24]

To solve this problem it is necessary to apply the concepts related to gravity as an expression of a celestial body, as well as the use of concepts such as centripetal acceleration, angular velocity and period.

PART A) The expression to find the acceleration of the earth due to the gravity of another celestial body as the Moon is given by the equation

g = \frac{GM}{(d-R_{CM})^2}

Where,

G = Gravitational Universal Constant

d = Distance

M = Mass

R_{CM} = Radius earth center of mass

PART B) Using the same expression previously defined we can find the acceleration of the moon on the earth like this,

g = \frac{GM}{(d-R_{CM})^2}

g = \frac{(6.67*10^{-11})(7.35*10^{22})}{(3.84*10^8-4700*10^3)^2}

g = 3.4*10^{-5}m/s^2

PART C) Centripetal acceleration can be found throughout the period and angular velocity, that is

\omega = \frac{2\pi}{T}

At the same time we have that centripetal acceleration is given as

a_c = \omega^2 r

Replacing

a_c = (\frac{2\pi}{T})^2 r

a_c = (\frac{2\pi}{26.3d(\frac{86400s}{1days})})^2 (4700*10^3m)

a_c = 3.34*10^{-5}m/s^2

3 0
3 years ago
The human ear canal is about 2.6 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the fu
Ugo [173]

Answer:

f = v/λ

 = v/4*L

 = 343 / 4 (0.026)

= 3120 Hz  

8 0
3 years ago
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