Answer:
The answer is Yes, the standing wave length with 5 anti-nodes will be created
Explanation:
To answer this question, we recall the frequencies of standing wave modes in a closed - closed tube of length (L).
The formula will now be:
Fₙ = n ( v/2L)
Where n = n is equal to the number of anti-nodes
and
lambda = 2L/n for standing waves in a closed tube where n is equal to the number of nodes
Now assuming the nodes are :
Where n = 1, 2, 3, 4, 5, ............
Now, we try to make "n" the subject of formula
Fₙ = n ( v/2L)
So therefore, the number of nodes produced will be
n = 2L Fₙ / v
2 x 0.55 x 10⁻² x 0.7 x 10⁶ / 1540
Calculating the above further, we arrive at = 5.
Now to answer the question,
The answer is Yes, the standing wave length with 5 anti-nodes will be created
